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3 years ago

The gram formula mass of a compound is 48 grams. the mass of 1.0 mole of this compound is

Chemistry

1 answer:

sergij07 [2.7K]3 years ago

7 0

If the mass of the compound is 48 grams, that would mean 1 mole of that compound would also he 48 grams

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2. Answer the following questions about a sample of calcium phosphate:

weqwewe [10]

Answer:

a) 310.18 g/mol

b) 4.352 moles Ca3(PO4)2

c) 2.6 * 10^24 molecules

d) 5.24 * 10^24 P atoms

e)13.056 moles Ca

f)10825.3 grams

Explanation:

Step 1: Data given

Atomic mass of Ca = 40.08 g/mol

Atomic mass of P = 30.97 g/mol

Atomic mass of O = 16.0 g/mol

Step 2: Calculate molecular weight of Ca3(PO4)2

Molecular weight of Ca3(PO4)2 = 3*atomic mass of Ca + 2* atomic mass of P and 8* atomic mass of O

Molecular weight of Ca3(PO4)2 = 3*40.08 + 2*30.97 + 8*16.0 = 310.18 g/mol

Step 3: Calculate moles of Ca3(PO4)2 in 1350 grams

Moles Ca3(PO4)2 = mass Ca3(PO4)2 /molar mass

Moles Ca3(PO4)2 = 1350 grams / 310.18 g/mol

Moles Ca3(PO4)2 = 4.352 moles

Step 4: Calculate molecules in 1350 grams

Molecules = moles * number of Avogadro

Molecules = 4.352 moles * 6.02 * 10^23

Molecules = 2.6 *10^24 molecules

Step 5: Calculate moles Phosphorus

For 1 mol Ca3(PO4)2 we need 2 moles P

For 4.352 moles Ca3(PO4)2 we have 2*4.352 = 8.704 moles

Step 6: Calculate P atoms

Atoms P = 8.704 moles * 6.02*10^23

Atoms P = 5.24 * 10^24 P atoms

Step 7: Calculate moles Calcium in 1350 grams

For 1 mol Ca3(PO4)2 we have 3 moles Ca

For 4.352 moles we have 3*4.352 = 13.056 moles Ca

Step 8: Calculate mass of 2.1 * 10^25 molecules of Ca3(PO4)2

Moles Ca3(PO4)2 = 2.1 * 10^25 / 6.02 * 10^23

Moles Ca3(PO4)2 = 34.9 moles

Mass Ca3(PO4)2 = 34.9 moles * 310.18 g/mol

Mass Ca3(PO4)2 = 10825.3 grams

4 0

3 years ago

Which scientific discipline is correctly matched to a contribution to society?

yKpoI14uk [10]

The scientific discipline that is correctly matched to a contribution to society would be geology linked to theory of continental drift ecology. Hope this answers the question. Have a nice day.

8 0

3 years ago

What us halfway between 7.5 and 10

serg [7]

10-7.5=2.5, 2.5/2=1.25, 7.5+1.25=8.75

6 0

3 years ago

How many milliliters of 0.132 m hclo4 solution are needed to neutralize 50.00 ml of 0.0789 m naoh?

Murljashka [212]

Answer: 29.89mL of HClO4 is needed

Explanation: Please see the attachments below

3 0

3 years ago

14. If 7.00 mol of PCI, and 5.00 mol of H2O react in the following chemical reaction, wind

Ymorist [56]

Answer:

Option A. H₂O

Explanation:

PCl3 + 3H2O → H3PO3 + 3HCI

From the equation,

We can see clearly that for every 3moles of H2O, 1mole of PbCl3 is needed. This clearly indicates that H2O is the limiting reactant. This can further be proved by doing the following:

From the equation,

1mole of PbCl3 required 3moles of H20.

Therefore, 7moles of PbCl3 will require = 7x3 = 21moles of H2O. This amount(i.e 21moles) of H20 is far greater than what was given (i.e 5moles of H2O) from the question.

Now let us consider the reverse case as follows:

From the equation,

1mole of PbCl3 required 3moles of H20.

Therefore, Xmol of PbCl3 will require 5moles of H2O i.e

Xmol of PbCl3 = 5/3 = 1.67moles

This amount(i.e 1.67moles of PbCl3) obtained is smaller than what was given (i.e 7moles of PbCl3) from the question.

This shows that PbCl3 is excess and H20 is the limiting reactant

6 0

3 years ago