A = s^2
A = 40
40 = s^2...by taking the square root of both sides, u eliminate the ^2
sqrt 40 = s
6.32 = s <===
See the attached figure.
<span>ad is a diameter of the circle with center p
</span>
∵ pd = radius = 7 ⇒⇒⇒ ∴ ad = 2 * radius = 2 * 7 = 14
∵ ae = 4 ⇒⇒⇒ ∴ ed = ad - ae = 14 - 4 = 10
∵ ad is a diameter
Δ acd is a triangle drawn in a half circle
∴ Δ acd is a right triangle at c
∵ bc ⊥ ad at point e
By applying euclid's theorem inside Δ acd
∴ ce² = ae * ed
∴ ce² = 4 * 10 = 40
∴ ce = √40 = 2√10 ≈ 6.325
The answer is S it’s the midpoint
Y=mx+b
m=slope
b=yint
find slope
slope between (x1,y1) and (x2,y2) is (y1-y2)/(x1-x2)
given
(-3,5) and (1,1)
slope=(5-1)/(-3-1)=4/-4=-1
y=-1x+b
find b
when x=1, then y=1
1=-1(1)+b
1=-1+b
add 1
2=b
y=-x+2
Answer: The point of intersection is (0,4).
Step-by-step explanation: