A rectangular portrait has an area of 40 square feet it's perimeter is 26 feet what are the dimensions of the portrait?
1 answer:
Answer:
Step-by-step explanation:
Portrait is in the shape of a rectangle.
And the area of a rectangle = Length × Width
Let the length of the portrait = l
And width of the portrait = w
Area of the portrait = lw
lw = 40
l =
Perimeter of a rectangle = 2(Length + width)
Perimeter of the portrait = 2(l + w)
26 = 2(l + w)
l + w = 13 ----------(2)
By substituting the value of 'l' in equation (1) from equation (2)
40 + w² = 13w
w² - 13w + 40 = 0
w² - 8w - 5w + 40 = 0
w(w - 8) - 5(w - 8) = 0
(w - 5)(w - 8) = 0
w = 5, 8 feet
From equation (2)
l = 8, 5 feet
Therefore, dimensions of the portrait are (5 feet by 8 feet) Or (8 feet by 5 feet).
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Answer:
Only the isosceles trapezoid has an area of 32 cm².
Step-by-step explanation:
Let's calculate the area of each polygon.
For the two triangles we have:
This polygon does not have an area of 32 cm².
For the rectangle we have:
This polygon does not have an area of 32 cm².
For the rectangle trapezoid we have:
So, this polygon does not have an area of 32 cm².
Finally, for the isosceles trapezoid:
This polygon does have an area of 32 cm².
Therefore, only the isosceles trapezoid has an area of 32 cm².
I hope it helps you!