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Drupady [299]
3 years ago
6

The spinners shown below are each spun one time. A spinner with 3 equal sections labeled 1 through 3.A spinner with 4 equal sect

ions labeled 1 through 4. What is the probability that both spinners will land on 2?
Mathematics
1 answer:
jenyasd209 [6]3 years ago
3 0

Answer:

the probability of both spinners land  on 2 is 1/12

Step-by-step explanation:

god bless you mark me as brainsliest please

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The ratio of ducks to geese in a pond is 3 : 5. There are 27 ducks.<br> How many geese are there?
Gemiola [76]

Answer:

D:G-------> 3:5

27/3=9

9 x 5= 45

45 geese

7 0
3 years ago
A bag contains marbles numbered 1 through 100. Zoe draws a marble. Then, without replacing the marble, she draws a second marble
Neporo4naja [7]
If starting out, there are 100 marbles and Zoe pulls out a 5 and doesn't replace it, then there are 99 marbles left to choose from. So, there are 9 digits 1-10 (not including #5) making the proportion you have left 9/99 which simplifies to 1/11
6 0
3 years ago
Help me with this please
11Alexandr11 [23.1K]
63/12 = 4.2

4.2 x 12 = 50.4

x = 50.4
7 0
3 years ago
Consider this equation: –3x – 5 2x = 6which is an equivalent equation after combining like terms?
Alla [95]
-3x-5+2x=6
2x-3x-5=6
-1x-5=6
-x-5=6
-x=11
x=11
an equivilent equaiton is x=11
7 0
3 years ago
When the sample size and the sample proportion remain the same, a 90 percent confidence interval for a population proportion p w
deff fn [24]

Answer:

A 90% confidence interval for <em>p</em> will be <u>narrower </u>than the 99% confidence interval.

Step-by-step explanation:

The formula to compute the (1 - <em>α</em>) % confidence interval for a population proportion is:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

Here \hat p is the sample proportion.

The margin of error of the confidence interval is:

MOE= z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The MOE is dependent on:

  1. Confidence level
  2. Standard deviation
  3. Sample size

The MOE is directly related to the confidence level and standard deviation.

So if any of the two increases then the MOE also increases, thus widening the confidence interval.

And the MOE is inversely related to the sample size.

So if the sample increases the MOE decreases and vice versa.

It is provided that the sample size and the sample proportion are not altered.

The critical value of <em>z</em> for 90% confidence level is:

z_{\alpha/2}= z_{0.10/2}=z_{0.05}=1.645

And the critical value of <em>z</em> for 99% confidence level is:

z_{\alpha/2}= z_{0.05/2}=z_{0.05}=1.96

So as the confidence level increases the critical value increases.

Thus, a 90% confidence interval for <em>p</em> will be narrower than the 99% confidence interval.

6 0
3 years ago
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