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Aleksandr [31]
3 years ago
15

Tangent is positive in quadrants 1 and 4 only ture or false

Mathematics
1 answer:
faltersainse [42]3 years ago
3 0
True because you are actually quadrant 1 is all positives
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Equation: у них
natali 33 [55]

Answer:

the answers for this problem will equal the equation. So it's y=1/3x+5

6 0
3 years ago
What is 7 and 1/2 minus 3/4
Sliva [168]

Answer:

here's your answer in the given picture

8 0
2 years ago
Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total
dimulka [17.4K]
You can set up a system of equations for this problem. x= number of coach tickets and y = number of first class tickets.

$210x + $1200y = $10,230 (cost of coach ticket plus cost of first class tickets is total budget)

x + y = 11 (number of coach tickets plus number of first class tickets is total number of people)

Solve the second equation for y to get y = 11 - x, then plug that into the first equation and solve for x:

$210x + $1200(11 - x) = $10,230

$210x + $13,200 - $1200x = $10,230

-$990x + $13,200 = $10,230

-$990x = $2,970

x = 3


Sarah bought x = 3 coach tickets. Plug that into the second equation and solve for y:

3 + y = 11

y = 8


Sarah bought y = 8 first class tickets.
6 0
3 years ago
Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7  y coordinate=-2

B: x coordinate=1  y coordinate=-2

C: x coordinate=1  y coordinate=-8

D: x coordinate=-7  y coordinate=-8

G: x coordinate=2  y coordinate=5

H: x coordinate=6  y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

The distance between A and B is 8

y coordinate of Vertices AC:

y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis  with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that <em>the measure of ABCD is twice GHJK.</em>

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in<em> y coordinate of Vertices GJ is 3.</em>

<em />

Points J and K could be located at:

J(2,2)

K(6,2)

3 0
3 years ago
A car rental company rents cars for x dollars per day plus y dollars for each mile driven. Carlos rented a car for 4 days, drove
topjm [15]

Answer:

x = $20/day, y = $0.35/mile

Step-by-step explanation:

x = $/day, y = $/mile

4x + 160y = 136

1x + 240y = 104

You can solve by elimination or substitution.

4 0
2 years ago
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