X-1%x^2-2x-3 =0
X-1=0
X=1 , ≠-1 , x≠3
Answer X=1
Hi friend,
If you flipped the graph y=x^2+2x-2 vertically, you would get the graph y=-(x^2+2x-2) TRUE.
Hope this helps you!
Answer:
They are at the same height at 1.13 seconds.
Step-by-step explanation:
Remark
The rockets are at the same height when f(x) = g(x) [see below] are the same. So you can equate them.
Givens
f(x) = - 16x^2 + 74x + 9
g(x) = -16x^2 + 82x I have changed this so you don't have 2 f(x)s
Solution
- f(x) = g(x)
- -16x^2 + 74x + 9 = -16x^2 + 82x Add: 16x^2 to both sides
- -16x^2+16x^2+74x + 9 = -16x^2+16x^2 + 82x Combine terms
- 74x + 9 = 82x Subtract 74x from both sides
- 74x - 74x + 9 = 82x - 74x Combine
- 9 = 8x Divide by 8
- 9/8 = 8x/8
- x = 1 1/8 Convert to decimal
- x = 1.125
- x = 1.13 [rounded]
|Ω| = 6 - number of all results
A = {1, 3} → |A| = 2 - number of (a) results
P(A) = 2/6 = 1/3