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3 years ago

Help me please!!!!!!!

Mathematics

1 answer:

Sav [38]3 years ago

3 0

Answer:

- sign between 9 and 64 under root, it should be + sign

Step-by-step explanation:

(-4)*(-8)(2)= 64

It should read x= √9+64 but not √9-54 which lead to incorrect solution

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Lim x->pi/3 ((2cosx-1)/(tan^2x-3))

beks73 [17]

You can check that the limit comes in an undefined form:

$\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\dfrac{0}{0}$

In these cases, we can use de l'Hospital rule, and evaluate the limit of the ratio of the derivatives. We have:

$\dfrac{\text{d}}{\text{d}x}2\cos(x)-1 = -2\sin(x)$

and

$\dfrac{\text{d}}{\text{d}x}\tan^2(x)-3 = 2\dfrac{\tan(x)}{\cos^2(x)}=\dfrac{2\sin(x)}{\cos^3(x)}$

So, we have

$\displaystyle \lim_{x\to\frac{\pi}{3}} \frac{2\cos(x)-1}{\tan^2(x)-3}=\lim_{x\to\frac{\pi}{3}} \dfrac{-2\sin(x)}{\frac{2\sin(x)}{\cos^3(x)}}=\lim_{x\to\frac{\pi}{3}}-\cos^3(x)=-\cos^3\left(\dfrac{\pi}{3}\right)$

6 0

3 years ago

ME LO RESUELVEN PORFAA

EastWind [94]

The hypotenuseb of the triangle is 17.

3 0

2 years ago

The graph below displays the wrist circumferences and heights of six students in Alyssa’s classroom.

coldgirl [10]

Answer:

Option D(No because the wrist circumference of 16 cm is paired with two heights.

Step-by-step explanation:

In the given graph we have set of points representing the wrist circumferences and heights of six students in Alyssa’s classroom.

x axis represents the wrist circumference while y axis represent the height.

Any relation is called a function if for one value of x we have only one value of y. If the graph passes the vertical line test that is if a vertical line drawn touches the graph at only one point then the graph is called a function.In the given graph for x value x=16 there are two y values 162 and 165.So the graph is not a function.

Among all the options Option D(No because the wrist circumference of 16 cm is paired with two heights.) is the right answer.

5 0

3 years ago

Read 2 more answers

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper

Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that $p = 0.3$

14 of these containers of paper.

This means that $n = 14$

What is the probability that John finds less than 7 golden sheets of paper?

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068$

$P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407$

$P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134$

$P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943$

$P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290$

$P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963$

$P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262$

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067$

90.67% probability that John finds less than 7 golden sheets of paper

7 0

2 years ago

What is the center and radius of the circle with equation x2 + y2 - 4x + 22y + 61 = 0?

lesantik [10]

Hello,

$x^2+y^2-4x+22y+61=0\\\\
(x^2-4x+4) +(y^2+22y+121)-121-4+61=0\\\\
(x-2)^2+(y+11)^2=64


$

Center is (2,-11) and radius is 8

6 0

3 years ago