12-7=5
10-5=5
is that what you where looking for?
Answer:
2 (real) solutions.
Step-by-step explanation:
A quadratic always has two solutions, whether they are real or complex.
Sometimes the solution is complex, involving complex numbers (2 complex), sometimes they are real and distinct (2 real), and sometimes they are real and coincident (still two real, but they are the same).
In the case of
x^2+3x = 3, or
x² + 3x -3 = 0
we apply the quadratic formula to get
x = (-3 +/- sqrt(3^2+4(1)(3))/2
to give the two solutions
{(sqrt(21)-3)/2, -(sqrt(21)+3)/2,}
both of which are real.
Answer:
4
Step-by-step explanation:
Given algebraic expression: 6x^3y+7x^2+5x+46x3y+7x2+5x+4
We know that the constants are the terms in the algebraic expression that contain only numbers.
In the given expression only last term has only numerical value and no variable, rest of them have variable x.
Therefore, the constant term in the given algebraic expression 6x^3y+7x^2+5x+46x3y+7x2+5x+4 is
77/5=99/x
77x=5*99
77x=495
x=495/77
x=6.4
she needs to study 6.4 hrs to get 99
Answer:
4.908
Step-by-step explanation:
Expanded Notation Form:
4
+ 0.9
+ 0.00
+ 0.008
Expanded Factors Form:
4 × 1
+ 9 × 0.1
+ 0 × 0.01
+ 8 × 0.001
Expanded Exponential Form:
4 × 100
+ 9 × 10-1
+ 0 × 10-2
+ 8 × 10-3
Word Form:
four and nine hundred eight thousandths
