Equation

How does scale factor affect the change in area?

MrRa [10]

<h3>Answer:</h3>

<u>It squares the amount you scaled it by.</u>

<h3>Step-by-step explanation:</h3>

For example, imagine that you had 2 by 2 square, and then you put it through a scale factor of 2.

Now each side length would be double of what it once was.

But when you multiply the new lengths together, the area would be of 4 times more.

(Original Equation) 2 * 2 = 4

(Scale Factor of 2) 4 * 4 = 16

So when the scale factor is made, the area would be squared to the multiple that you scaled it by.

<em>***A square root is a number times itself.</em>

<em>9 and 225 would be the square root in these problems.</em>

7 0

3 years ago

A car with an initial cost of $26,500 depreciates at a rate of 7.5% per year. Write the function that models this situation. The

solniwko [45]

Answer:

f(x) = 26500 * (0.925)^x

It will take 7 years

Step-by-step explanation:

A car with an initial cost of $26,500 depreciates at a rate of 7.5% per year. Write the function that models this situation. Then use your formula to determine when the value of the car will be $15,000 to the nearest year.

To find the formula we will use this formula: f(x) = a * b^x. A is our initial value which in this case is $26500. B is how much the value is increasing or decreasing. In this case it is decreasing by 7.5% per year. Since the car value is decreasing we will subtract 0.075 from 1. This will result in the formula being f(x) = 26500 * (0.925)^x. Now to find the value of the car to the nearest year of when the car will be 15000 we plug 15000 into f(x). 15000 = 26500 * (0.925)^x. First we divide both side by 26500 which will make the equation: 0.56603773584=(0.925)^x. Then we will root 0.56603773584 by 0.925. This will result in x being 7.29968 which is approximately 7 years.

4 0

4 years ago

A sample of 1200 computer chips revealed that 45% of the chips fail in the first 1000 hours of their use. The company's promotio

yaroslaw [1]

Answer:

$z=\frac{0.45 -0.48}{\sqrt{\frac{0.48(1-0.48)}{1200}}}=-2.08$

$p_v = P(Z$

So the p value obtained was a low value and using the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of chips that fail in the first 1000 hours of their use is not significantly less than 0.48.

Step-by-step explanation:

Data given and notation

n=1200 represent the random sample taken

$\hat p=0.45$ estimated proportion of chips that fail in the first 1000 hours of their use

$\mu_0 =0.48$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion si less then 0.48:

Null hypothesis: $p\geq 0.48$

Alternative hypothesis: $p < 0.48$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.45 -0.48}{\sqrt{\frac{0.48(1-0.48)}{1200}}}=-2.08$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v = P(Z$

So the p value obtained was a low value and using the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of chips that fail in the first 1000 hours of their use is not significantly less than 0.48.

6 0

4 years ago

shanes neighbor pledged 1.25 for every 0.5 miles that shane swims in the charity swim-a-thon.if Shane swims 3 miles,how much mon

Paraphin [41]

3/0.5 = 6
6 x 1.25 = 7.50

4 0

4 years ago

Read 2 more answers

Write the equation of the line parallel to y=3x-2 that passes through (3, 2) in point-slope form

AleksandrR [38]

Substitute the x and y values from (3,2).

Formula: y=mx+b

2= 3(3)+b
2-9= -7

y=3x-7

5 0

3 years ago