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3 years ago

9x+10y=29 10x+9y=28 Solve by elimination

Mathematics

1 answer:

Temka [501]3 years ago

5 0

There’s this app called Photomath. It’s free! You can download it and it’ll solve your problem quick! ;P

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A ________ is a range of values between which the value of the population parameter is believed to be, along with a probability

nignag [31]

The best answer out of the ones provided would be c, confidence interval

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3 years ago

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Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

Correct answer:

A. I and II

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

Correct answer:

A. I and II

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3 years ago

Sum is 9 product is 8

bekas [8.4K]

The answer is eight and one.
Sum: 8 + 1=9
Product:8*1=8

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First person to comment gets brainliest

bearhunter [10]

Answer:

Step-by-step explanation:

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3 years ago

How do you solve: g(x) = x - 2 ( I think the answer is 2 but how?!)

babymother [125]

Answer:

x-2 =0

x=2

Step-by-step explanation:

we take -2 to the anther side it becomes 2

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3 years ago

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