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tankabanditka [31]
3 years ago
11

What is the value of the expression 10p - 5/5+3(p- 1)

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
6 0
10p-5/5+3(p-1)
10p-1+3p-3
Combine the line terms
13p-4
Hope this help
DaniilM [7]3 years ago
3 0
Hi,

10p-5/5+3(p-1)
10p-1+3p-3
10p+3p-1-3
13p-4

Hope this is helpful!
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Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side
lorasvet [3.4K]

Answer:

Step-by-step explanation:

1.

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

       =cot x (sec²x)²

       =cot x (1+tan²x)²     [ ∵ sec²x=1+tan²x]

       =  cot x(1+ 2 tan²x +tan⁴x)

       =cot x+ 2 cot x tan²x+cot x tan⁴x

        =cot x +2 tan x + tan³x        [ ∵cot x tan x =\frac{ \textrm{tan x }}{\textrm{tan x}} =1]

       =R.H.S

2.

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

 L.H.S =(sin x)(tan x cos x - cot x cos x)

          = sin x tan x cos x - sin x cot x cos x

           =\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}

           = sin²x -cos²x

           =1-cos²x-cos²x

           =1-2 cos²x

           =R.H.S

         

3.

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

         =1+\frac{{sin^2x}}{cos^2x}                       [\textrm{sec x}=\frac{1}{\textrm{cos x}}]

         =1+tan²x                        [\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]

         =sec²x

        =R.H.S

4.

\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}

L.H.S=\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}

       =\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}

      =\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}

     =\frac{\textrm{2sin x}}{sin^2 x}

      = 2 csc x

    = R.H.S

5.

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

        = sec²x-tan²x

        =\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}

        =\frac{1- sin^2x}{cos^2x}

        =\frac{cos^2x}{cos^2x}

        =1

     

       

8 0
3 years ago
Course Home
kolbaska11 [484]

Answer:

........... .........

3 0
3 years ago
Which statement is true
loris [4]

Answer:


Step-by-step explanation


You must find the common denominator for all of them.  


A is correct. 13 x 2 is 26 and 14 x 2 is 28. Therefore, 13/14 is greater than 25/28.


B is not correct. 4 x 5 is 20 and 9 x 5 is 45. 4/9 is actually less than 21/45.


C is not correct. 5 x 2 is 10 and 6 x 2 is 12. 5/6 is actually less than 11/12.


D is not correct. 4 x 5 is 20 and 5 x 5 is 25. 4/5 is actually less than 8/25.

4 0
2 years ago
Please help me out !
VashaNatasha [74]

Answer:

i dont know lol but anyways

Step-by-step explanation:

5 0
2 years ago
Find the distance between ( -2, 5) (-2, 14).
WITCHER [35]

Answer:

9

Step-by-step explanation:

x didn't change in value, y changed by 9

the distance between the two points is 9

6 0
2 years ago
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