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3 years ago

URGENT PLEASE!!!!!!!!!!!!

Mathematics

2 answers:

blondinia [14]3 years ago

8 0

Answer:

its x=16 :)))

kondaur [170]3 years ago

6 0

Answer:

i got 178

Step-by-step explanation:

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What is the approximate radius of a sphere with a volume of 1436cm to power of 3

Margarita [4]

Answer:

<h3>The radius is 7 cm</h3>

Step-by-step explanation:

Volume of a sphere is given by

$V = \frac{4}{3} \pi {r}^{3}$

where r is the radius

From the question V = 1436 cm³

$1436 = \frac{4}{3} \pi {r}^{3}$

Multiply through by 3

We have

$4308 = 4\pi {r}^{3}$

Divide both sides by 4π

${r}^{3} = \frac{4308}{4\pi}$

${r}^{ 3} = \frac{1077}{\pi}$

Find the cube root of both sides

$r = \sqrt[3]{ \frac{1077}{\pi} }$

r = 6.99

We have the final answer as

Hope this helps

3 0

2 years ago

A jar of M&M’s : 24 brown , 13 orange, 15 red , 10 green , 15 yellow , and 10 blue. Jim is blindfolded and will draw a singl

pshichka [43]

Answer: 24/87 or 8/29

Step-by-step explanation:

24+13+15+10+15+10=87, the total amount of M&M's.

24 are brown, so 24/87 chance that he will draw a brown one.

24/87 = 8/29 simplified.

3 0

2 years ago

Elise has a budget of thirty dollars to spend on back-to-school clothes. she finds some shirts she likes that cost fifteen dolla

Alexandra [31]

X is equal to 2 because thirty divide fifteen is two

5 0

2 years ago

MATH IS HARD. HELP<br> Change the following into a single fraction: 1− (a+b/a−b)

lianna [129]

Answer:

-2b/(a-b)

Step-by-step explanation:

1− (a+b/a−b)

We need to get a common denominator of a-b

1 = (a-b)/(a-b)

Replace 1 with (a-b)/(a-b)

(a-b)/(a-b) - (a+b)/(a-b)

Put over the common denominator

(a-b) - (a+b)

-----------------

(a-b)

Distribute the minus sign.

(a-b) - a-b)

-----------------

(a-b)

a-a-b-b

---------------

a-b

-2b

----------

a-b

6 0

2 years ago

H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?

zubka84 [21]

$H(x)=(x^2)+1\ \ \ \ and\ \ \ \ K(x)=-(x^2)+4. \\\\K(H)=-(H^2)+4=-(x^2+1)^2+4=4-(x^2+1)^2=\\\\.\ \ \ =2^2-(x^2+1)^2=(2-x^2-1)(2+x^2+1)=(1-x^2)(3+x^2)=\\\\.\ \ \ =(1-x)(1+x)(x^2-3\cdot i^2)=(1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)\\\\ K(H)=0\ \ \ \ \Leftrightarrow\ \ \ (1-x)(1+x)(x- \sqrt{3} \cdot i)(x+ \sqrt{3} \cdot i)=0\\\\x=1\ \ \ \ or\ \ \ \ x=-1\ \ \ \ or\ \ \ \ x=\sqrt{3} \cdot i\ \ \ \ or\ \ \ \ x=-\sqrt{3} \cdot i\\\\Ans.\ e.$

4 0

2 years ago