Please help me find the area for this hexagon (please show work to) ,:)

Mathematics

1 answer:

kvasek [131]2 years ago

4 0

Check the picture below.

so the area of the hexagon is really just the area of two isosceles trapezoids.

$\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=2 \end{cases}\implies \begin{array}{llll} A=\cfrac{2(2+4)}{2}\implies A=6 \\\\\\ \stackrel{\textit{twice that much}}{2A = 12} \end{array}$

You might be interested in

Solve the system of equations

nekit [7.7K]

Answer: x = 3 and y = 1

Step-by-step explanation:

y = - x + 4 ............... equation 1

y = x - 2 ............. equation 2

Solving the linear equation by substitution method , we have :

substitute equation 2 into equation 1 , that is

x - 2 = - x + 4

Add 2 to both sides , we have

x = -x + 4 + 2

Add x to both sides , we have

2x = 6

divide through by 2

x = 3

Substitute x = 3 into equation 2 to find the value of y , we have

y = x - 2

y = 3 - 2

y = 1

Therefore : x = 3 and y = 1

8 0

3 years ago

Use the given graph to determine the limit, if it exists. (4 points)

skelet666 [1.2K]

<h3>Answer: 3</h3>

Explanation:

Refer to the graph below. It should be similar to what your teacher gave you, based off the description.

Since we're approaching 3 from the right side, this means we'll be working with the horizontal line portion. We could start at something like x = 3.2 and move closer to 3 by getting to x = 3.1 then x = 3.01 then x = 3.001 and so on. We never actually get to 3 itself.

As x gets closer to 3 from this direction, the y values are approaching 3 since every point on this horizontal line has the same y coordinate. Technically the y value is already at 3, but it's the same idea.

In terms of notation, we can write $\displaystyle \lim_{x\to3^{+}}f(x) = 3$