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nikklg [1K]
3 years ago
6

Xy = –16. What is the constant of variation for this relationship?

Mathematics
1 answer:
olganol [36]3 years ago
6 0
Direct variation is y=kx and inverse variation is y=k/x, in this case:

y=-16/x

So this is an inverse variation with a constant of -16
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Peter added the following fractions<br><br>Is Peter correct?
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Step-by-step explanation:

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Which of the following statements would not translate to the equation 8 ÷ x = -4?
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If anyone can solve this quickly I will give brainly
Nataly [62]

Answer:

m∠BFE  = 171º

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3 years ago
Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.&lt;b
kherson [118]
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Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

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Therefore, the probability that <span>all three cards are queens is given by

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Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

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Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
8 0
3 years ago
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