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vodomira [7]
3 years ago
5

The reciprocal of 8 over 11 is?

Mathematics
2 answers:
ikadub [295]3 years ago
7 0

The reciprocal of 8/11 is:

11/8


11 over 8


Like Turning the Number Upside Down

dog  upside down  

We can think of a whole number as being "number/1", so the reciprocal is just like "flipping it over":


Number   Reciprocal

5 =  51     15

8 =  81     18

1000 =  10001     11000

For Fractions, Flip the Whole Fraction Over

Example: the reciprocal of 3/4 is 4/3



Rufina [12.5K]3 years ago
3 0

The reciprocal of a basic fraction is just the fraction itself upside down. In this scenario, the answer would be

11/8

Hope this helps you. :)

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A speed walker covered 4 1/2 mi in 3/4 hour. How far will he walk in 3/4 hour if he walks?
Nezavi [6.7K]

Given:

Consider the complete question is "A speed walker covered 4\dfrac{1}{4} mi in \dfrac{3}{4} hour. How far will he walk in 3/4 hours if he walks twice as fast?"

A speed walker covered 4\dfrac{1}{4} mi in \dfrac{3}{4} hour.

To find:

Distance covered by him if in 3/4 hour if he walks twice as fast.

Solution:

We have,

Distance=4\dfrac{1}{2}=\dfrac{9}{2}

It means a speed walker covered \dfrac{9}{2} mi in \dfrac{3}{4} hour.

If the speed is twice then he can cover double distance is same time.

Distance covered by him if in 3/4 hour if he walks twice as fast is

2\times \dfrac{9}{2}=9

Therefore, distance covered by him is 9 mi.

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3 years ago
Help me please !<br> 4,5 and 6
andreev551 [17]

9514 1404 393

Answer:

  4a. ∠V≅∠Y

  4b. TU ≅ WX

  5. No; no applicable postulate

  6. see below

Step-by-step explanation:

<h3>4.</h3>

a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...

  ∠V≅∠Y

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b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...

  TU ≅ WX

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<h3>5.</h3>

The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)

  "No, we cannot prove they are congruent because none of the five postulates or theorems can be used."

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<h3>6.</h3>

The first statement/reason is always the list of "given" statements.

1. ∠A≅∠D, AC≅DC . . . . given

2. . . . . vertical angles are congruent

3. . . . . ASA postulate

4. . . . . CPCTC

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