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2 years ago

In how many ways can a committee of 3 men and 2 women can be formed from 7 men and 5 women?

Mathematics

1 answer:

dezoksy [38]2 years ago

5 0

Answer:

in five (5) ways a committee can be formed from 7 men and 5 women

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-.25 x+1.3=-.55x-.2 find x

Mamont248 [21]

You need to isolate the variable my dividing each side by factors that don’t contain the variable
x=-5

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2 years ago

HELP!!!

xz_007 [3.2K]

Step-by-step explanation:

Given that the graph shows the normal distribution of the length of similar components produced by a company with a mean of 5 centimeters and a standard deviation of 0.02 centimeters.

A component is chosen at random, the probability that the length of this component is between 4.98 centimeters and 5.02

=P(|z|<1) (since 1 std dev on either side of the mean)

=2(0.3418)

=0.6826

=68.26%

The probability that the length of this component is between 5.02 centimeters and 5.04 centimeters is

=P(1<z<2) (since between 1 and 2 std dev from the mean)

=0.475-0.3418

=0.3332

=33.32%

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3 years ago

Read 2 more answers

Simplify (x/3-2)(x/2-3)

Rudik [331]

x²/6 - 2x + 6

I am not too sure but I hope that this helps

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2 years ago

Question 15 Unsaved Which biconditional is NOT a good definition? Question 15 options: A whole number is odd if and only if the

skad [1K]

We see that the second definition is not a good definition. We want both parts to have the same truth value, but we see that we can have two angles created by a ray that are not equal. That means the antecedent is false but the consequence is true, which means it's not an iff statement, and a bad definition in this context.

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2 years ago

Again ... Commute times in the U.S. are heavily skewed to the right. We select a random sample of 500 people from the 2000 U.S.

VladimirAG [237]

Answer:

We conclude that the mean commute time in the U.S. is less than half an hour.

Step-by-step explanation:

We are given that a random sample of 500 people from the 2000 U.S. Census is selected who reported a non-zero commute time.

In this sample the mean commute time is 27.6 minutes with a standard deviation of 19.6 minutes.

Let $\mu$ = mean commute time in the U.S..

So, Null Hypothesis, $H_0$ : $\mu \geq$ 30 minutes {means that the mean commute time in the U.S. is more than or equal to half an hour}

Alternate Hypothesis, $H_A$ : $\mu$ < 30 minutes {means that the mean commute time in the U.S. is less than half an hour}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean commute time = 27.6 minutes

s = sample standard deviation = 19.6 minutes

n = sample of people from the 2000 U.S. Census = 500

So, the test statistics = $\frac{27.6 -30}{\frac{19.6}{\sqrt{500} } }$ ~ $t_4_9_9$

= -2.738

The value of t test statistic is -2.738.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical values of -1.645 at 499 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of t as -2.378 < -1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean commute time in the U.S. is less than half an hour.

4 0

3 years ago

In how many ways can a committee of 3 men and 2 women can be formed from 7 men and 5 women?​

In how many ways can a committee of 3 men and 2 women can be formed from 7 men and 5 women?