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Orlov [11]
3 years ago
15

Write an equivalent expression for (m+5)(m-3)

Mathematics
1 answer:
AleksandrR [38]3 years ago
4 0

Solve using the foil method (first, outside, inside, last).

(m + 5)(m - 3)

Your steps using foil should look like:

  1. m * m
  2. m * -3
  3. 5 * m
  4. 5 * -3

After multiplying, rewrite your expression.

m² - 3m + 5m - 15

The last step to simplifying this expression is to combine like terms, which are -3m + 5m.

<h3>m² + 2m - 15</h3>
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Step-by-step explanation:

It is.

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Find two numbers, if their sum is (−1/3) and their difference is 18. PLEASE HELP
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X+y=-1/3
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4 years ago
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djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

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Substitue 20 in for x

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