Find the slope of a line that passes through (7,-6) and (-5,-8)

Mathematics

1 answer:

AfilCa [17]3 years ago

3 0

Change in x over change in y

(y2-y1)/(x2-x1)
(-8--6)/(-5-7)
-2/-12
slope = 1/6

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Given the following recurrence relation: An=(−2)An−1, with A0=(−1)

kirill [66]

Technically you could answer this one by one, by substituting n with 1, 2, 3, 4, then 5. Like here:
A1=(-2)A1-1
=(-2)A0, then substituting A0 with -1...
=(-2)(-1)
Which would mean A1=2. Then..
A2=(-2)A2-1
A2=(-2)A1
A2=(-2)(2)
Which would mean A2=-4.
By repeating this process you'd eventually get A4..
A5=(-2)A4
if you did the steps right you'd get that A4 is -16..
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Zigmanuir [339]

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Step-by-step explanation:

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Given the data points, (x, y) of a linear function: (2, 11), (4, 10), (6, 9), (12, 6), what is the function? What is the slope?

NeX [460]

Answer:

The function is $y~=~12 ~-~ 0.5 \cdot x$ .

The slope is $m=-0.5$ .

The y-intercept is $b=12$ .

Step-by-step explanation:

Our aim is to calculate the values m (slope) and b (y-intercept) in the equation of a line :

$y=mx+b$

We have the following data:

$\begin{array}{c|cccc}x&2&4&6&12\\y&11&10&9&6\end{array}$

To find the line of best fit for the points given, you must:

Step 1: Find $X\cdot Y$ and $X\cdot X$ as it was done in the table below.

Step 2: Find the sum of every column:

$\sum{X} = 24 ~,~ \sum{Y} = 36 ~,~ \sum{X \cdot Y} = 188 ~,~ \sum{X^2} = 200$

Step 3: Use the following equations to find b and m:

$\begin{aligned} b &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 36 \cdot 200 - 24 \cdot 188}{ 4 \cdot 200 - 24^2} \approx 12 \\ \\m &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 4 \cdot 188 - 24 \cdot 36 }{ 4 \cdot 200 - \left( 24 \right)^2} \approx -0.5\end{aligned}$