The distance from E to side AD is 25/13.
<h3>
What is a distance?</h3>
- The length of the line connecting two places is the distance between them.
- If the two points are on the same horizontal or vertical line, the distance can be calculated by subtracting the non-identical values.
To find what is the distance from E to side AD:
- If you draw a diagram, you'll see that triangle AEB is a right triangle with lengths 5, 12, and 13.
- Let's call F the point where E meets side AD, so the problem is to find the length of EF.
- By Angle-Angle Similarity, triangle AFE is similar to triangle BEA. (the right angles are congruent, and both angle FAE and ABE are complementary to angle BAE)
- Since they're similar, the ratios of their side lengths are the same.
- EF/EA = EA/AB (they're corresponding side lengths of similar triangles).
Substitute them with known lengths:
- EF/5 = 5/13
- EF = 5 × (5/13) = 25/13
Therefore, the distance from E to side AD is 25/13.
Know more about distance here:
brainly.com/question/2854969
#SPJ4
The correct answer is given below:
Square ABCD has side lengths of 13 units. Point E lies in the interior of the square such that AE=5 units and BE=12 units. What is the distance from E to side AD? Express your answer as a mixed number.
Answer:
726
Step-by-step explanation:
Here p = k / q², and 24 = k / 121, or k = 2904
Then p = 2904 / q²
If q = 2, p = 2904 /4 = 726
Answer:
A: 244 pounds
B: 122 pounds
C: 274 pounds
Step-by-step explanation:
We have A+B+C = 640; A=2B; C=A+30. Substituting the last into the first gives ...
A + B + (A +30) = 640
2A +B = 610 . . . . . . . . . . . . subtract 30
Substituting the second into this equation gives ...
2(2B) +B = 610
B = 610/5 = 122 . . . . . divide by 5
A = 2B = 244 . . . . . . . .find A from B
C = A+30 = 274 . . . . . find C from A
Box A weighs 244 pounds; box B weighs 122 pounds; box C weighs 274 pounds.
Answer: 321 for #1 and 52 for #2
Step-by-step explanation: I divided and got 321 for #1 and 52 for #2.
