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Vsevolod [243]
3 years ago
5

George has $15. He would like to know if he has enough money to see a movie ($9.00) and buy a pretzel ($2.65), a drink ($1.35),

and two veggie cups ($1.74 each). George incorrectly used this numerical expression to decide if he had enough money. 15 - 9 + 2.65 + 1.35 + 2(1.74) Use the order of operations to simplify this expression.
Mathematics
2 answers:
Eduardwww [97]3 years ago
8 0

Answer:

13.48

Step-by-step explanation:

13.48

Tatiana [17]3 years ago
4 0

Answer:

13.48

Step-by-step explanation:

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The figure shows a model of a roof truss. Based on the markings, which triangles are congruent? State the reason.
Travka [436]

Answer:

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2 years ago
What’s 10x - 4 - 7/2x - 3/4(2x - 3) in its simplest form?
lyudmila [28]
10x-4-7/2x-3/4(2x-3)
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decimal form:
6.5-4-1.5x-2.25
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7 0
3 years ago
Evaluate the double integral.
Fynjy0 [20]

Answer:

\iint_D 8y^2 \ dA = \dfrac{88}{3}

Step-by-step explanation:

The equation of the line through the point (x_o,y_o) & (x_1,y_1) can be represented by:

y-y_o = m(x - x_o)

Making m the subject;

m = \dfrac{y_1 - y_0}{x_1-x_0}

∴

we need to carry out the equation of the line through (0,1) and (1,2)

i.e

y - 1 = m(x - 0)

y - 1 = mx

where;

m= \dfrac{2-1}{1-0}

m = 1

Thus;

y - 1 = (1)x

y - 1 = x ---- (1)

The equation of the line through (1,2) & (4,1) is:

y -2 = m (x - 1)

where;

m = \dfrac{1-2}{4-1}

m = \dfrac{-1}{3}

∴

y-2 = -\dfrac{1}{3}(x-1)

-3(y-2) = x - 1

-3y + 6 = x - 1

x = -3y + 7

Thus: for equation of two lines

x = y - 1

x = -3y + 7

i.e.

y - 1 = -3y + 7

y + 3y = 1 + 7

4y = 8

y = 2

Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7

∴

\iint_D 8y^2 \ dA = \int^2_1 \int ^{-3y+7}_{y-1} \ 8y^2 \ dxdy

\iint_D 8y^2 \ dA =8 \int^2_1 \int ^{-3y+7}_{y-1} \ y^2 \ dxdy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( \int^{-3y+7}_{y-1} \ dx \bigg)   dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( [xy^2]^{-3y+7}_{y-1} \bigg ) \ dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( [y^2(-3y+7-y+1)]\bigg ) \ dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ([y^2(-4y+8)] \bigg ) \ dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( -4y^3+8y^2 \bigg ) \ dy

\iint_D 8y^2 \ dA =8 \bigg [\dfrac{ -4y^4}{4}+\dfrac{8y^3}{3} \bigg ]^2_1

\iint_D 8y^2 \ dA =8 \bigg [ -y^4+\dfrac{8y^3}{3} \bigg ]^2_1

\iint_D 8y^2 \ dA =8 \bigg [ -2^4+\dfrac{8(2)^3}{3} + 1^4- \dfrac{8\times (1)^3}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [ -16+\dfrac{64}{3} + 1- \dfrac{8}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{64-8}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{56}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [  \dfrac{-45+56}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [  \dfrac{11}{3}\bigg]

\iint_D 8y^2 \ dA = \dfrac{88}{3}

4 0
2 years ago
Can you guys help me please!!
ella [17]

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\huge\bold\red{{Answer:}}

1.C

2.C

3.D

4.D

5.D

6.A

7.C

8.B

9.A

10.C

11.A

12.B

13.D

14.C

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7 0
3 years ago
2u^2 + v when u=3 and v=7
Mariana [72]

Answer: 25

Step-by-step explanation:

There are two variables which is u and v and is given that u is 3 and v is 7  so input that into the expression and solve.

2(3)^2 + 7      Solve the exponent first

2(9) + 7      Now multiply then add

18 + 7 = 25

5 0
3 years ago
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