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maria [59]
3 years ago
6

Write the number that completes the analogy. X^2 is to 121 as x^3 is to _____​

Mathematics
1 answer:
crimeas [40]3 years ago
3 0

Answer:

1331

Step-by-step explanation:

Since 121 is a perfect square you can take the square root of it to figure out what x equals then just take what x equals and cube it.

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Your EZ Pass account begins with $80. It costs you $4/day. Write an equation
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Answer:

The equation is A(d) = 80 - 4d

Step-by-step explanation:

Linear function:

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This means that A(0) = 80, m = 4

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How do I put 8 and one half into fraction form?
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Answer:

Step-by-step explanation:

8 + 1/2

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192 fl oz = how many pt  
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A student at a four-year college claims that average enrollment at four-year colleges is higher than at two-year colleges in the
Kitty [74]

Answer:

a) Since we have sample data and we don't know the population deviation we can use the t distribution in order to test the hypothesis

t would represent the statistic

b) t=\frac{(\bar X_{2}-\bar X_{1})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)  

The degrees of freedom are given by df=n_1 +n_2 -2=35+35-2=68  Replacing the info given we got:

t=\frac{(5216-5069)-0}{\sqrt{\frac{4773^2}{35}+\frac{8141^2}{35}}}}=0.0921  

c) p_v =P(t_{68}>0.0921)=0.463  

Since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean of enrollment is significantly higher for four year college than for two year college

Step-by-step explanation:

Information given

\bar X_{1}=5069 represent the mean for two year colleges

\bar X_{2}=5216 represent the mean for four year college

s_{1}=4773 represent the sample standard deviation for 1  

s_{2}=8141 represent the sample standard deviation for 2  

n_{1}=35 sample size for the group 2  

n_{2}=35 sample size for the group 2  

\alpha=0.05 Significance level provided

Part a

Since we have sample data and we don't know the population deviation we can use the t distribution in order to test the hypothesis

t would represent the statistic

Part b

We want to test if the mean of enrollment for four year college is higher than for two year college, the system of hypothesis would be:  

Null hypothesis:\mu_{2}-\mu_{1} \leq 0  

Alternative hypothesis:\mu_{2} - \mu_{1} > 0  

The statistic is given by:

t=\frac{(\bar X_{2}-\bar X_{1})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)  

The degrees of freedom are given by df=n_1 +n_2 -2=35+35-2=68  Replacing the info given we got:

t=\frac{(5216-5069)-0}{\sqrt{\frac{4773^2}{35}+\frac{8141^2}{35}}}}=0.0921  

Part c

The p value would be given by:

p_v =P(t_{68}>0.0921)=0.463  

Since the p value is higher than the significance level we don't have enough evidence to conclude that the true mean of enrollment is significantly higher for four year college than for two year college

6 0
4 years ago
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