Answer:
Follows are the solution to the given point:
Step-by-step explanation:
In point a:
¬∃y∃xP (x, y)
∀x∀y(>P(x,y))
In point b:
¬∀x∃yP (x, y)
∃x∀y ¬P(x,y)
In point c:
¬∃y(Q(y) ∧ ∀x¬R(x, y)) 
∀y(> Q(y) V ∀ ¬ (¬R(x,y)))
∀y(¬Q(Y)) V ∃xR(x,y) )
In point d:
¬∃y(∃xR(x, y) ∨ ∀xS(x, y))
∀y(∀x>R(x,y)) 
∃x>s(x,y))
In point e:
¬∃y(∀x∃zT (x, y, z) ∨ ∃x∀zU (x, y, z))
∀y(∃x ∀z)>T(x,y,z) ∀x ∃z> V (x,y,z))
The equation must equal 84, so you can eliminate B and D.
Chin charges a rate for 2 hours, then charges a reduced rate for 4 hours. There are no discounts present in his rate, so you can eliminate A.
The equation for Chin's charges can be found by the equation C. 2x + 4y = 84.
Answer:
Step-by-step explanation:
80, 82, 88, 90, 100
Now cross out the numbers starting with 80 and 100 and keep going till you get the middle number which would be 88
Answer:
t =12 m
Step-by-step explanation:
We can use similar triangles and proportions to solve this problem.
Put the smaller triangle on top and the larger triangle on bottom
12 9
------ = -------
16 t
Solve by using cross products
12 t = 9*16
12 t =144
Divide by 12
12t/12 = 144/12
t = 12
Answer:
33x2=66
66-3=62
62x4=248
Is this a question for a test cause if it is i'm gonna feel embarrassed
