Answer:
cement by 5 Kg
Step-by-step explanation:
add the parts of the ratio, 5 + 4 + 1 = 10 parts
Divide the quantity of concrete by 10 to find the value of one part of the ratio.
110Kg ÷ 10 = 11Kg ← value of 1 part of ratio , thus
5 parts = 5 × 11Kg = 55Kg ← cement required
4 parts = 4 × 11Kg = 44Kg ← sand required
1 part = 11Kg ← gravel required
He requires 55Kg of concrete but only has 50Kg.
He requires 44Kg of sand and has 55Kg
He requires 11Kg of gravel and has 15Kg
Thus he is 5Kg short of cement.
Sorry wanna points bfbdjudi
B. Is the right answer
First you have to take the common elements then use an identity/formula to get the rest
x^3 - 3x^2 + x-3
x^2 (x-3) +1 (x-3)
(x^2 +1) (x-3)
(x-1)(x+1)(x-3) {using a^2-b^2 on x^2-1^2}
False. A two-column proof is also known as a "Statement-Reason Proof", with the statement column on the left and the reason column on the right.
Answer:
59 / 71
Step-by-step explanation:
Given the data :
A B C Total
Male 20 10 13 43
Female 15 2 11 28
Total 35 12 24 71
The probability of randomly selecting a Student that got B ;
Probability = required outcome / Total possible outcomes
P(getting B) = number of students who got B / total number of students
P(getting B) = 12 / 71
Probability of getting B = 12 /71
Probability of not getting B = P(getting B)' = 1 - P(getting B)
Probability that student did not get "B" = 1 - 12/71 = 59 / 71
