Solution:
Using Substitution Method:
-4x+7y=-5 (Equation 1)
x-3y=-5 (Equation 2)
get the value of x from Equation 2
x=3y-5 (Equation 3)
Put the value of x from Equation 3 in Equation 1
-4(3y-5)+7y=-5
-4(3y)+20+7y=-5
-12y+7y=-5-20
-5y=-25
Negative sign on both sides cancels each other
y=25/5
y=5
Putting value of y in equation 3
x=3(5)-5
x=15-5
x=10
Therefore, [x,y]=[10,5]
Using Elimination Method
-4x+7y=-5 (Equation 1)
x-3y=-5 (Equation 2)
Multiply equation 2 with -4 in order to eliminate the x term
-4(x-3y)=-5*4
-4x+12y=20 (Equation 3)
Adding Equation 1 and 3
-4x+7y=-5
-4x+12y=20
+ - = - (Change Of Sign with x and y terms)
-----------------
0x-5y = -25
-5y=-25
y=5
Substituting y’s value is Equation 1
-4x+7(5)=-5
-4x+35=-5
-4x=-40
Cancellation of negative sign on both sides
x=40/4
x=10
[x,y]=[10,5]
Answer:
Step-by-step explanation:
<u>We know that:</u>
- Some squares are 100% shaded, and some are half shaded.
- Half shaded squares: 10 squares
- 100% shaded: 20 squares
- Area of figure = Area of half shaded + Area of 100% shaded
<u>Solution:</u>
- Area of figure = Area of half shaded + Area of 100% shaded
- => Area of figure = (10 x 1/2) + 20
- => Area of figure = 5 + 20
- => Area of figure = 25 units²
Hence, the area of the figure is 25 units².
when u have a common a denominator then you just add the numerator that would be 7 and 9. 7 + 9= 16
so ur solution would be 16/22 and then u would simplify by dividing both values by 2.
so the solution is8/11
1x^3*3x^5
=(1*3)(x^(3+5))
=3x^8
Answer:
2 outcomes
Step-by-step explanation:
Let's list count all the possible outcomes:
(1,3) (1,4) (1,5) (1,6)
(2,3) (2,4) (2,5) (2,6)
(3,3) (3,4) (3,5) (3,6)
As expected, there are 12 (3x4) possible outcomes.
How many outcomes do not show an even number (so showing 1 or 3) on the first spinner and show a 6 on the second spinner?
There are two cases where 6 is on the second spinner and NOT an even number on the first spinner: (1,6) and (3,6)
