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inna [77]
3 years ago
12

Choose the right answer which year had higher profit in month 3 ?

Mathematics
2 answers:
monitta3 years ago
7 0

Answer:

Where is month 3 I will comment the answer if there is a graph or table to know!!! For house for economics. Sorry I don't understand...

Step-by-step explanation:

Setler [38]3 years ago
5 0

Answer:

Last year

Step-by-step explanation:

The question is:

Which year had a decrease in profit between months 3 and 4?

The answer is last year

I hope this helps!

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Help please? This is my homework for today so yea
MrRa [10]
The volume equals length x width x height so multiply all of those with a calculator and you’ll get your answer hope I helped :)
8 0
3 years ago
Read 2 more answers
Each of 11 refrigerators of a certain type has been returned to a distributor because of an audible, high-pitched, oscillating n
Pie

Answer:

The correct answer is 1,51%

Step-by-step explanation:

To get the probability  equally likely of the first 6 examined that have a defective compressor, we use the following formula

P=# of possibilities that meet the condition / #of equally likely possibilities.

As there are multiple events ,  and all must be achieve, we multiply the probabilities.

P1=7 / 11

P2=6 / 10

P3=5 / 9

P4=4 / 8

P5=3 / 7

P6=2 / 6

P(x)=7 / 11*6 / 10*5 / 9*4 / 8*3 / 7*2 / 6=0,01515151515

P(x)=1,51%

3 0
3 years ago
Dr. Jon planned to reward his class with candy because everyone got a A on the test. He surveyed every 4th student that entered
USPshnik [31]
This is an example of a systematic sample.

Dr. Jon developed a system in order to get a random sample. His plan was to survey the 4th student that entered his classroom.
8 0
3 years ago
Solve 2x3 + x2 - 15x completely by factoring.
Ludmilka [50]
2x^3+x^2-15x factored completely would be: <em>x(x+3)(2x-5).</em> Not sure which answer choice but I hope that I was some help.
8 0
3 years ago
Find 2 numbers a and b such that (a-b)^2 &lt; (a+b)(a-b)&lt; (a+b)^2 Find two numbes a and b such that this is not true
Svet_ta [14]

Suppose for the moment that the inequality holds for all a,b:

(a-b)^2

Expanding everything gives

a^2-2ab+b^2

\implies-ab

In particular, the inequality says that -ab for any choice of a,b. But if a and b>0, then -ab>0 while ab.

So one possible choice of a,b could be a=-1 and b=1. Then we get

(-1-1)^2=4

(-1+1)(-1-1)=2

(-1+1)^2=0

but clearly it's not true that 4.

8 0
3 years ago
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