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Vika [28.1K]
3 years ago
12

What step gets you closer to the solution of this equation 5•(x-2)=7

Mathematics
1 answer:
viktelen [127]3 years ago
5 0
You do 5 times x and -2 so you’d get 5x-10=7. Then add 10 to both sides to get 5x=17 and divide 17/5 to get 3.4
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3/8 times what equals 1
horsena [70]
3/8 times 8/3 = 1
Answer=8/3
6 0
3 years ago
Adam plans to choose a video game from a section of the store where everything is 75% off. He writes the expression −0.75 to fin
Salsk061 [2.6K]

Answer:

Step-by-step explanation:

Adam plans to choose a video game from a section of the store where everything is 75% off.

The expression written by him for this situation is d - 0.75d.

Here, the part d represents the sale price before discount and the part 0.75d is the discount amount.

The expression written by Rena is 0.25d.

Here, the part 0.25d is the price after discount. Since 75% is the discount, the rate after disount is 25% and 25% of d is 0.25d.

6 0
3 years ago
C. Supercomputers have been developed that are much larger and can
harkovskaia [24]

Answer:

   4.485 × 〖10〗^10  x    1.3268 × 〖10〗^11 =

   (4.485 x1.3268) ×( 〖10〗^11× 〖10〗^10)

              5.950    x  〖10〗^21

Step-by-step explanation:

6 0
2 years ago
Someone please help !! I don’t know what I’m doing with this !!
dimulka [17.4K]

Answer:

  a) d(sinh(f(x)))/dx = cosh(f(x))·df(x)/dx

  b) d(cosh(f(x))/dx = sinh(f(x))·df(x)/dx

  c) d(tanh(f(x))/dx = sech(f(x))²·df(x)/dx

  d) d(sech(4x+2))/dx = -4sech(4x+2)tanh(4x+2)

Step-by-step explanation:

To do these, you need to be familiar with the derivatives of hyperbolic functions and with the chain rule.

The chain rule tells you that ...

  (f(g(x)))' = f'(g(x))g'(x) . . . . where the prime indicates the derivative

The attached table tells you the derivatives of the hyperbolic trig functions, so you can answer the first three easily.

__

a) sinh(u)' = sinh'(u)·u' = cosh(u)·u'

For u = f(x), this becomes ...

  sinh(f(x))' = cosh(f(x))·f'(x)

__

b) After the same pattern as in (a), ...

  cosh(f(x))' = sinh(f(x))·f'(x)

__

c) Similarly, ...

  tanh(f(x))' = sech(f(x))²·f'(x)

__

d) For this one, we need the derivative of sech(x) = 1/cosh(x). The power rule applies, so we have ...

  sech(x)' = (cosh(x)^-1)' = -1/cosh(x)²·cosh'(x) = -sinh(x)/cosh(x)²

  sech(x)' = -sech(x)·tanh(x) . . . . . basic formula

Now, we will use this as above.

  sech(4x+2)' = -sech(4x+2)·tanh(4x+2)·(4x+2)'

  sech(4x+2)' = -4·sech(4x+2)·tanh(4x+2)

_____

Here we have used the "prime" notation rather than d( )/dx to indicate the derivative with respect to x. You need to use the notation expected by your grader.

__

<em>Additional comment on notation</em>

Some places we have used fun(x)' and others we have used fun'(x). These are essentially interchangeable when the argument is x. When the argument is some function of x, we mean fun(u)' to be the derivative of the function after it has been evaluated with u as an argument. We mean fun'(u) to be the derivative of the function, which is then evaluated with u as an argument. This distinction makes it possible to write the chain rule as ...

  f(u)' = f'(u)u'

without getting involved in infinite recursion.

7 0
3 years ago
And items are for $40 plus sales tax on the item is 8% what is the sales tax on the total cost
Setler79 [48]

Answer:

43.20 for the total cost of the item

6 0
3 years ago
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