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zavuch27 [327]
3 years ago
5

Suppose the correlation between height and weight for adults is 0.80. What proportion (or percent) of the variability in weight

can be explained by the relationship with height
Mathematics
1 answer:
gulaghasi [49]3 years ago
8 0

Answer: 64% of the variability in weight can be explained by the relationship with height.

Step-by-step explanation:

  • In statistics, Correlation coefficient is denoted by 'r' is a measure of the strength of the relationship between two variables.
  • Coefficient of determination, r^2, is a measure of variability in one variable can be explained variation in the other.

Here, r= 0.80

\Rightarrow\ r^2= (0.80)^2=0.64

That means 64% of the variability in weight can be explained by the relationship with height.

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Answer:

5 x (4+y)

Step-by-step explanation:

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3 years ago
PLEASE HELP!!!!!!!!!!!!! DUE SOON
Sergio039 [100]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ h=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{65}t


now, take a look at the picture below, so for 2) and 3) is the vertex of this quadratic equation, 2) is the y-coordinate and 3) the x-coordinate.


\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ h=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+65}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left( -\cfrac{65}{2(-16)}~~,~~0-\cfrac{65^2}{4(-16)} \right) \implies \left( \cfrac{65}{32}~,~0- \cfrac{4225}{-64}\right)


\bf \left( \cfrac{65}{32}~,~0+ \cfrac{4225}{64}\right)\implies \left( \stackrel{seconds}{2\frac{1}{32}}~~,~~ \stackrel{feet~hight}{66\frac{1}{64}}\right)

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A prism and its representation to the right as a ?<br> 1)pyramid<br> 2)box<br> 3)net<br> 4)house
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emmainna [20.7K]
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