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Fittoniya [83]
3 years ago
12

Solve. 5y - 10 = -25 Pls explain

Mathematics
2 answers:
daser333 [38]3 years ago
5 0
5y-10=-25 
Move constant to the right by adding its opposite to both sides
5y-10+10=-25+10
Eliminate the opposites
5y=-25+10

-25+10
Keep the sign of the number with the lager absolute value and subtract the smaller absolute value from the larger
-(25-10)
Subtract the nubers
-15
5y=-15
Divide both sides of the equation by 5
5y/5=-15/5
any expression divided by itself equals 1
y=-15/5
calculate the quatient
y=-3
Ira Lisetskai [31]3 years ago
4 0
5y-10=-25
5y=-25+10 addition property of equa
5y=-15 simplifying
Y=-15/5 dividing property
Y=-3
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Cos (theta) = square of 2 / 2, and 3*pi/2 < theta < 2*pi, evaluate sin (theta) and tan (theta)
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Step-by-step explanation:

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3 years ago
Dale bought a map of his city it uses a scale of 1 inch = 8 miles Dale house and school are 1 1/2 inches apart on the map how fa
shtirl [24]
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Here's a fast way. 1 inch is 8 miles, and half of 8 equals 4 miles, which is 1/2 of an inch., 8 + 4 = 12 miles. 

So if his house and the school were 12 miles apart, and we we're using the 1 inch. = 6 miles scale, then it'd be 2 inches on the map. 

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4 0
3 years ago
If f(1) = 2 – 2 anid 9(37)<br> and g(x) = x2 – 9, what is the domain of g(x) = f(x)?
lana66690 [7]

Answer:

B

Step-by-step explanation:

Let divide g(x) by f(x)

\frac{ {x}^{2} - 9 }{2 - x {}^{ \frac{1}{2} } }

The domain of a rational function cannot equal zero so let set the bottom function to zero.

2 - x {}^{ \frac{1}{2} }  = 0

x  {}^{ \frac{1}{2} }  = 2

Square both sides

x = 4

Also we can simplify the bottom denomiator into a square root function

2 -  \sqrt{x}

The domain of a square root function is all real number greater than or equal to zero because a square root of a negative number isn't graphable.

So we must find a answer that

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  • Range out in positve infinity
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8 0
2 years ago
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JulsSmile [24]
X = 0.89
x = -0.89
two solutions
6 0
3 years ago
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