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Fittoniya [83]
3 years ago
12

Solve. 5y - 10 = -25 Pls explain

Mathematics
2 answers:
daser333 [38]3 years ago
5 0
5y-10=-25 
Move constant to the right by adding its opposite to both sides
5y-10+10=-25+10
Eliminate the opposites
5y=-25+10

-25+10
Keep the sign of the number with the lager absolute value and subtract the smaller absolute value from the larger
-(25-10)
Subtract the nubers
-15
5y=-15
Divide both sides of the equation by 5
5y/5=-15/5
any expression divided by itself equals 1
y=-15/5
calculate the quatient
y=-3
Ira Lisetskai [31]3 years ago
4 0
5y-10=-25
5y=-25+10 addition property of equa
5y=-15 simplifying
Y=-15/5 dividing property
Y=-3
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loris [4]

\huge\bf  \pink {\underline{Solution :-}}

2 {a}^{2}  + 7a - 15

= 2 {a}^{2}  + 10a - 3a - 15

= 2a(a + 5) - 3(a + 5)

= (a + 5)(2a - 3)

\sf \red{Hence, Answer \:  is  \: (a + 5)(2a - 3).}

\\

\bf \purple{ \underline{ Important  \: Formulas  \: for  \: Factorization :-}}

• \:  {a}^{2}  + 2ab + {b}^{2} =  {(a + b)}^{2}

• \: (a + b)(a - b) =  {a}^{2}  -  {b}^{2}

• \:  {a}^{2} - 2 ab  +  {b}^{2}  =  {(a - b)}^{2}

• \:  {a}^{3}  + 3 {a}^{2} b + 3a {b}^{2}  +  {b}^{3} =  {(a + b)}^{3}

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•  \:  {(a + b)}^{2}  +  {(a - b)}^{2}  = 2( {a}^{2}  +  {b}^{2} )

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• \:   {( \frac{a + b}{2} )}^{2}  - ( {\frac{a - b}{2} } )^{2}  = ab

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