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3 years ago

5

The graph if a function is always a straight line true or false

1 answer:

HACTEHA [7]3 years ago

4 0

This statement is false. Graphs of functions are NOT always straight lines.

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What is the product of (6x3+3x)(x2+4)

ki77a [65]

If you would like to know what is the product of (6 * x^3 + 3 * x) * (x^2 + 4), you can calculate this using the following steps:

(6 * x^3 + 3 * x) * (x^2 + 4) = 6 * x^3 * x^2 + 6 * 4 * x^3 + 3 * x * x^2 + 3 * 4 * x = 6 * x^5 + 24 * x^3 + 3 * x^3 + 12 * x = 6 * x^5 + 27 * x^3 + 12 * x

The correct result would be 6 * x^5 + 27 * x^3 + 12 * x.

3 0

3 years ago

Write the equation of the line that passes through the point (-5,5) and has a slope of -8/5

Free_Kalibri [48]

Answer:

The equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

$y=-\frac{8}{5}x-3$

Step-by-step explanation:

Given

$\left(x_1,\:y_1\right)=\left(-5,5\right)$

$m=\frac{-8}{5}$

Point-Slope Form equation is

$\left(y-y_1\right)=m\left(x-x_1\right)$

$\left(y-5\right)=\frac{-8}{5}\left(x-\left(-5\right)\right)$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$y-5=\frac{-8}{5}\left(x+5\right)$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$y-5=-\frac{8}{5}\left(x+5\right)$

$y-5+5=-\frac{8}{5}\left(x+5\right)+5$

$y=-\frac{8}{5}x-3$

Therefore, the equation of the line that passes through the point (-5,5) and has a slope of -8/5 will be:

$y=-\frac{8}{5}x-3$

5 0

3 years ago

A baker has determined that four every<br> 4 pounds of flour, she can make 6<br> loaves of bread.

Darya [45]

Hi! Where is the rest of this question

3 0

2 years ago

Alejandra and her father tile a bathroom floor. They used 48 tiles that measure 1 foot on a side. One side of the bathroom is 8

Phantasy [73]

Answer:

6

Step-by-step explanation:

48 tiles divided by 8 ft is 6 ft

5 0

3 years ago

I need this problem solve quick

belka [17]

Answer:

52

Step-by-step explanation:

The missing sides is equal to the opposite side

So add all the sides up

3 0

2 years ago