Answer:
40
Step-by-step explanation:
Plug x=-9 in. -9-8+(-9×(-8)) -15=-17+72-15=-17+72-15=40. I hope this helped!
Answer:
5(4-1)
Step-by-step explanation:
5(4-1)
20-5
5x4= 20
5x1= 5
Answer:
wow no sabría como ayudarte
Let x be the volume (liters) of pure (at 100%) acid needed
Let y be the volume (liters) of the other acid (at 10%) needed
The final solution will be:
a) x+ y = 63 liters, AND their respective concentration in acid: is
100% x & 10% :y that will generate 63 liters at 20%
b) x +0.1 y = 63x 0.2 = 12.6
Let's solve this system of 2 equations:
x + y =63
x + 0.1 y = 12.6
Solving it will give you:
x= 7 liters at 100%
y = 56 liters at 10%
Answer:
There is a 33.72% probability that the total weight of the passengers exceeds 4500 pounds.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
There are 22 passengers. Passengers average 190 pounds in the summer, including clothing and carry-on baggage. But passengers vary, and the FAA did not specify a standard deviation. A reasonable standard deviation is 35 pounds. This means that
.
What is the approximate probability that the total weight of the passengers exceeds 4500 pounds?
This probability is 1 subtracted by the pvalue of Z when
. So



has a pvalue of 0.6628.
This means that there is a 1-0.6628 = 0.3372 = 33.72% probability that the total weight of the passengers exceeds 4500 pounds.