Your LCM is 11880 , and your HCF is 36
We are given
A dog runs from point O to B
t(OA)=2.3 s
t(OC)=4.1 s
now, we can find time between A and C
t(AC)=t(OC)-t(OA)
t(AC)=4.1-2.3
t(AC)=1.8 s
we are given
distance between A and C is 4m
so,
d=4m
now, we can find average velocity between A and C

we can plug values


so, option-C..................Answer
Answer:
x=14.87
Step-by-step explanation:
What we want to use is pythagoras theorem:
a^2+b^2=c^2, where c is the hypotenuse
10^2+11^2=x^2
221=x^2
x=
x=14.866...
x=14.87
Its the first one. I typed them all in my graphing calculator to check
Answer:
no expression is equal to -20