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Jet001 [13]
3 years ago
14

Javier rounded to the nearest half to estimate the product of 3 and two-fifths and Negative 3 and StartFraction 7 over 8 EndFrac

tion. How do the estimate and the actual product compare?
Mathematics
2 answers:
7nadin3 [17]3 years ago
8 0

Answer:

The actual product is less than the estimate. The numbers differ by more than one.

Step-by-step explanation:

i took the test

BaLLatris [955]3 years ago
3 0

Answer:

The actual product is less than the estimate. The numbers differ by more than one

Step-by-step explanation:

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Find the value of a in the parallelogram.
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If 30 gallons of water are poured into 1/5 -gallon containers, how many full containers can be filled?
statuscvo [17]
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2 years ago
50 POINTS!!! jamie will choose between two catering companies for an upcoming party. company A chargers a set-up fee of $500 plu
Shtirlitz [24]

Answer:

60 guests

Step-by-step explanation:

We'll say that the number of guests is n.

We're looking for the n where both of these expressions are equal:

Company A (500 set-up fee, 25 for each guest)

500 + 25 * n

Company B (200 set-up fee, 30 for each guest)

200 + 30 * n

500 + 25n = 200 + 30n

Subtract 200 from both sides.

300 + 25n = 30n

Subtract 25n from both sides.

300 = 5n

We'll reverse the sides.

5n = 300

Divide both sides by 5.

n = 300/5 = 60

Thus, both companies are equal when n is 60, or when there are 60 guests.

5 0
2 years ago
Read 2 more answers
Solve the quadratic for x, then enter the numerical value of your solution. (If there are two solutions, either one will work.)
xz_007 [3.2K]

Answer: X= -1 OR X= 11

Step-by-step explanation:

Step 1 : Equate ( x-5)² since it occurred twice, hence the reason 2 is added in front of (x-5)²

= (x-5)²

= (x-5)(x-5)

= (x²-5x-5x+25)

= (x²-10x+25)

Step 2: multiply the result by two since it occurs twice and also bring the equation

= 2 (x²-10x+25) +7 = 79

= 2x²- 20x+50+7 = 79

= 2x²- 20x+57 =79

Step 3: most quadratic equation are always equal to zero, let's make this one equal to Zero by subtracting 79 from both sides

= 2x²-20x+57-79 = 79-79

= 2x²-20x-22=0

Step 4: divide the equation by a common number to get the least coefficient of the three coefficients

Dividing the three by 2

(2x²-20x-22)/2 = x²- 10x- 11

Step 5: Factorise completely

Sub step 1 : the first term in the equation is X² which makes the first term coefficient 1; the second term in the equation is -10x which makes the second term coefficient -10, the constant has a coefficient of -11

Sub step 2: multiply the coefficient of the first term (1) and the constant (-11) which gives us (-11)

1*-11 = -11

Sub step 3: Get two numbers in such a way that the addition of the first number and the second number gives the second coefficient in the quadratic equation and the multiplication of the two numbers will give us the product of the first coefficient and the constant.

And the two numbers is +1 and -11, the sum of the two numbers will give us -10 and the product will give us -11.

Step 6: slot the two numbers (+1, -11) into the equation by making themr replace the second coefficient

x²-10x-11=0

= x²+x-11x-11 =0

Step 7: split the equation into two and Factorise further

= (x²+x)(-11x-11) =0

= x(x+1)-11(x+1) = 0

= x+1= 0 or x-11 =0

Step 8 split them into individual equation

= x+1= 0.

Subtract 1 from both sides

= X+1-1=0-1

= x= -1

Or X should be

= x-11=0

Add 11 to both sides

= X-11+11 = 0+11

= x= 11

6 0
2 years ago
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