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3 years ago

Please show all work for this 7x + 3 =9x - 7

1 answer:

8 0

<u>7x + 3 = 9x - 7</u>

Subtract 7x from each side: + 3 = 2x - 7

Add 7 to each side: 10 = 2x

Divide each side by 2 : <em>5 = x </em>

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PLEASE HELP ASAP!! LUL

yawa3891 [41]

Answer:

Step-by-step explanation:

it should add up to 360°

360=135 + 120 + 7x-64+5x-4+3x+31+4x+15+6x-8 (seems like too much huh)

360=225+25x ( much better just add the x terms and the constants together)

135 = 25x ( just subtract 225 from each side of the equation)

5.4 = x ( divide 135 by 25 )

4 0

3 years ago

If I could get help………

charle [14.2K]

Answer:

$x1 = 3 \\ y1 = 10 \\ x2 = 5 \\ y2 = 12 \\ y - y1 = \frac{y2 - y1}{x2 - x1} (x - x1) \\ y - 10 = \frac{2}{2} (x - 5) \\ y = x - 5 + 10 = x + 5$

enjoy it

8 0

3 years ago

What is seven times 5

Elodia [21]

Answer:

35 cuh

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6 0

3 years ago

Classify a triangle with each set of side lengths as acute, right, or obtuse

Serga [27]

Answer: Acute- (2,3,3.5) Right-(2.5,6,6.5) obtuse- (7,8,12), (7,9,14)

Step-by-step explanation:

6 0

3 years ago

Dubnium-262 has a half-life of 34 s. How long will it take for 500.0 grams to

dmitriy555 [2]

Answer:

the time taken for the radioactive element to decay to 1 g is 304.8 s.

Step-by-step explanation:

Given;

half-life of the given Dubnium = 34 s

initial mass of the given Dubnium, m₀ = 500 grams

final mass of the element, mf = 1 g

The time taken for the radioactive element to decay to its final mass is calculated as follows;

$1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} = (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500}) = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s$

Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.

4 0

3 years ago