Answer:
Final answer is approx x=0.16.
Step-by-step explanation:
Given equation is 
Now we need to solve equation and round to the nearest hundredth.
Round to the nearest hundredth.
Hence final answer is approx x=0.16.
Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
The equation can be rewritten as x = -2/3 y, so x/y = -2/3
However, for y=0, the ratio is undefined as you would be dividing by 0??
The answer is c first 2×6= 12 then 12-5=7
then do -7×-2=14 the minus signs cancel
finaly we have two bracket so we multiply both number (7)×(14)=98
