All categories

3 years ago

Sean used candle molds, as shown below, to make candles that were perfect cylinders and spheres:

1 answer:

4 0

56.52 in^3

V(cylinder) = pi * r^2 * h
V = pi * 3^2 ^ 6
V = pi * 9 * 6
V = 54pi

V(sphere) = (4/3) * pi * r^3
V = (4/3) * pi * 3^3
V = (4/3) * pi * 27
V = 36pi

54pi - 36pi = 18 pi
18 * 3.14 = 56.52

You might be interested in

Solve 3(x +15) ≤5(x+2) + 15<br>

belka [17]

Answer:

x≥5

Step-by-step explanation:

3(x+15)≤5(x+2)+15

3x+45≤5x+10+15

3x+35≤5x+25

3x-5x≤25-35

-2x≤-10

x≥5

{x:xEx:6,7,8,9,10....}

Hope this helps ;) ❤❤❤

3 0

2 years ago

PLEASE HELP ME WITH MY MATH

Alina [70]

Answer:

Step-by-step explanation:

y is 3 times more than x.

X=0 Y=0 3x0=0

X=1 Y=3

X=2 Y=6

X=3 Y=9

X=4 Y=12

Then just plot it as co-ordinates (x,y)

Y is 1/4 of x. Divide by 4

X=0 Y=0

X=4 Y=1

X=8 Y=2

X=12 Y=3

X=16 Y=4

Then just plot it as co-ordinates (x,y)

8 0

2 years ago

Determinar el área de un hexágono que esta inscrito en una circunferencia de 4 unidades de radio

Dmitrij [34]

Answer:

espero y te sirva hay esta todo lo que necesitas

6 0

2 years ago

Could you help With these questions

Ganezh [65]

All I know is number 9. Is -2/5

5 0

3 years ago

Someone help me with this geometry homework !!!!!! 10 points!

Reil [10]

Answer: 3a = (0, 1) 3b = (2, 1) 3c = (2.5, 1) 3d = (1.6, 1)

4a = (2, 3.5) 4b = (2, 3) 4c = (2, 5.375)

<u>Step-by-step explanation:</u>

The length of AB is 6 and is horizontal (affects the x-coordinate)

$3a)\quad 6\bigg(\dfrac{1}{2}\bigg)\quad =3\qquad \qquad A(-2, 1) +(3, 0)= C(1,1)\\\\\\3b)\quad 6\bigg(\dfrac{2}{3}\bigg)\quad =4\qquad \qquad A(-2, 1) +(4,0)= C(2,1)\\\\\\3c)\quad 6\bigg(\dfrac{3}{4}\bigg)\quad =\dfrac{9}{2}\qquad \qquad A(-2, 1) +(4.5,0)= C(2.5,1)$

$3d)\quad 6\bigg(\dfrac{3}{5}\bigg)\quad =\dfrac{18}{5}\qquad \qquad A(-2, 1) +(3.6,0)= C(1.6,1)$

***********************************************************************************

The length of AB is 5 and is vertical (affects the y-coordinate)

$4a)\quad 5\bigg(\dfrac{1}{2}\bigg)\quad =\dfrac{5}{2}\qquad \qquad A(2, 1) +(0,2.5)= C(2,3.5)\\\\\\4b)\quad 5\bigg(\dfrac{2}{5}\bigg)\quad =2\qquad \qquad A(2, 1) +(0,2)= C(2,3)\\\\\\4c)\quad 5\bigg(\dfrac{7}{8}\bigg)\quad =\dfrac{35}{8}\qquad \qquad A(2, 1) +(0,4.375)= C(2,5.375)$

4 0

3 years ago