The scale factor of the dilation is

.
Notice how one unit of Q'P' can take up 3 units of QP.
Answer:
20 students should be on each float
Step-by-step explanation:
Number of seniors = 100
Number of juniors = 80
To find number of students that should be on each float, find highest common factor (H.C.F) of 100 and 80
Write prime factorisation of 100 and 80.
100 =
× 
80 =
× 5
So,
H.C.F(100, 80) =
× 5 = 4 × 5 = 20
Therefore,
20 students should be on each float
Answer:
13
Step-by-step explanation:
We're trying to find the distance between points X and Y. Or the distance of X-Z plus Z-Y.
Lets find the distance of X-Z
6-2=4
Now lets find the distance of Z-Y
15-6=9
Now we add the distances
4+9=13
Some fractions equivalent to 8/3 are 16/6, 24/9, and 32/12.
Answer:
C
Step-by-step explanation:
Given
A = 
Substitute the given values with h = a, then
16.5 =
( multiply both sides by 2 )
33 = a(a + 8) ← distribute
33 = a² + 8a ( subtract 33 from both sides )
0 = a² + 8a - 33 ← in standard form
0 = (a + 11)(a - 3) ← in factored form
Equate each factor to zero and solve for a
a + 11 = 0 ⇒ a = - 11
a - 3 = 0 ⇒ a = 3
However, a > 0 thus a = 3
Hence the height is 3 feet