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3 years ago

Help I don’t get this

Mathematics

1 answer:

Gekata [30.6K]3 years ago

8 0

Answer:

2.)4n>(n/2)^2

3. (The problem isn't clear)

4.)n^2+2n-3=129

5.)n-5=171

Step-by-step explanation:

2.)

4n(four times the number) >(larger than) (n/2)^2 (half the number squared)

4.)

Sum=addition

n^2 (number squared) +2n (twice the number)-3=129

5.)

N(unknown number of pages) -5(amount of pages already read)= 171(the number of pages it took her to finish)

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Any of these questions will be ok

Alekssandra [29.7K]

#7:

It means to solve for y.

#8:

We can write:

l = w + 2

Because it says the length is 2 more than the width.

3 0

3 years ago

Volume and surface area are often compared by manufacturers in order to maximize how much of something can go inside of a packag

notka56 [123]

We have no dimensions to work with. I'll pick some and try and comply with the conditions of the problem.

Suppose you have an object that is 14 by 22 by 27 cm. These three numbers have no common factor so they cannot be reduced any further, which is helpful for this problem.

Find the Volume
Volume

l = 27 cm
w = 14 cm
h = 22 cm

V = 27 *14 * 22
V = 8316 cm^3

Find the surface area
SA = 2*l*w + 2*l*h + 2*w*h
SA = 2*27*14 + 2*27*22 + 2*14*22
SA = 756 + 1188 + 616
SA = 2558

Just looking at these numbers The surface area is about 1/3 of the volume. I don't think this is always true.

$\frac{SA}{V} = \frac{2*L*W + 2*L*H + 2*W*H}{L*W*H}$

Another way to do this is to consider a cube which might give you a more useful result.

s = L = W = H all three dimensions are equal in a cube.
The volume of a cube is s*s*s = s^3
The surface area of a cube is 2*s*s + 2*s*s + 2s*s = 6s^2

$\frac{SA_cube}{V_cube} = \frac{6s*s}{s*s*s}$
$\frac{SA}{V} = \frac{6}{s}$

That means whatever the side length, the Surface Area to volume = 6/the side length which is kind of an interesting result.

4 0

3 years ago

Use substitution to solve this problem a=5, b=2 5a - b = ‽

Rom4ik [11]

Plug the numbers into the equation

5(5) - 2 = ?

25 -2 = 23

23

3 0

3 years ago

I need help ASAP. Thank you :)

kvasek [131]

m∠FDE = 52°

Solution:

Given data:

DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°

Sum of the adjacent angles in a straight line = 180°

m∠ABF + m∠CBF = 180°

116° + m∠CBF = 180°

m∠CBF = 64°

If CD || BE, then CD || BF.

Hence CD || BE and BE || FD.

Therefore BFCD is a parallelogam.

In parallelogram, Adjacent angles form a linear pair.

m∠CBF + m∠BFD = 180°

64° + m∠BFD = 180°

m∠BFD = 116°

Sum of the adjacent angles in a straight line = 180°

m∠BFD + m∠DFE = 180°

116° + m∠DFE = 180°

m∠DFE = 64°

we know that DE ≅ DF.

In triangle, angles opposite to equal sides are equal.

m∠DFE = m∠DEF

m∠DEF = 64°

sum of all the angles of a triangle = 180°

m∠DFE + m∠DEF + m∠FDE = 180°

64° + 64° + m∠FDE = 180°

m∠FDE = 52°

8 0

3 years ago

State what additional information is required in order to know that the triangles are congruent for the reason given. If possibl

earnstyle [38]

Answer:

XY ≅ TU

Step-by-step explanation:

SAS = side- angle- side

It requires two sides and the included angle be congruent.

Given one congruent side and one congruent adjacent angle.

In addition to what is given we need the other side be congruent too:

XY ≅ TU

8 0

3 years ago

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