Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
Answer:
x = 12
Step-by-step explanation:
10x = 120 original equation
10x/10 = 120/10 divide both sides by 10
x = 12 simplify
Check work:
10(12) = 120
120 = 120 (true)
Answer:
x = 0
, y = 7/6
Step-by-step explanation:
Solve the following system:
{18 y - 12 x = 21
6 x - 9 = -9
In the second equation, look to solve for x:
{18 y - 12 x = 21
6 x - 9 = -9
Add 9 to both sides:
{18 y - 12 x = 21
6 x = 0
Divide both sides by 6:
{18 y - 12 x = 21
x = 0
Substitute x = 0 into the first equation:
{18 y = 21
x = 0
In the first equation, look to solve for y:
{18 y = 21
x = 0
Divide both sides by 18:
{y = 7/6
x = 0
Collect results in alphabetical order:
Answer: {x = 0
, y = 7/6
Answer:
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Therefore the length of a side of a cube is ![\sqrt[3]{64}\ or\ 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%5C%20or%5C%204)
</h2>
Step-by-step explanation:
The volume of a cube is expressed as L³ where L is the length of each side of the cube.
Given volume of a cube = 64in³
On substituting;
64 = L³
Taking the cube root of both sides to determine L we have;
![\sqrt[3]{64} = (\sqrt[3]{L})^{3}\\\sqrt[3]{64} = L\\L=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%3D%20%28%5Csqrt%5B3%5D%7BL%7D%29%5E%7B3%7D%5C%5C%5Csqrt%5B3%5D%7B64%7D%20%3D%20L%5C%5CL%3D4)
Therefore the length of a side of a cube is ![\sqrt[3]{64}\ or\ 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%5C%20or%5C%204)
0 remainder of 6
Hope this helps