Answer:
Statements Justifications
E bisects AI, BC bisects AE, FH bisects EI Given
AE is congruent to EI Definition of Bisector
AD is congruent to DE Definition of Bisector
EG is congruent to GI Definition of Bisector
If AE is congruent to EI, AD is congruent to DE, and EG is congruent to GI, then AD is congruent to DE, EG, and GI, DE is congruent to AD, EG, and GI, EG is congruent to AD, DE, and GI, and GI is congruent to AD, DE, and EG. Therefore, AD is congruent to EG.
This isn't the best answer and probably won't get you a 100, but it shows effort so...
Answer:
0.3
Step-by-step explanation:
Answer: Option B is the correct answer
Step-by-step explanation:
The given expression is
(–7t – 5v)(–4t – 3v).
The product will be a quadratic equation (having 2 as the highest power)
To find the product, we would expand the brackets
(-7t × -4t )+ (-7t × -3v) + (-5v × -4t) + (-5v × - 3v)
= (- -28t^2) +(- -21tv) + (- - 20tv) +(- -15v^2)
Recall, negative × negative equals positive.
=28t^2 +21tv +20tv+ 15v^2)
Collecting like terms, we add all terms containing the same letters together
28t^2 + 41tv + 15v^2
Option B is the correct answer
Answer:
70 + 7x
Step-by-step explanation:
7(8+x+2)
Combine like terms in the parenthesis
7(8+2+x)
7(10+x)
Distribute
70 + 7x
