What object is considers two dimensional because it only has length and width

1 answer:

5 0

An example of a two dimensional object is a price of paper or a drawn figure on a paper because it has no height or depth

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Find the final price of a $149 iPod with a 10% discount<br> and 5% sales tax.

omeli [17]

Answer:

140.80

Step-by-step explanation:

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4 0

2 years ago

Line segment ab has endpoints a(9, 3) and b(2, 6). find the coordinates of the point that divides the line segment directed from

Dominik [7]

When we are to divide the line segment such that the ratio is 1:2, there are actually 3 parts of the segment. First, we determine the distance between the coordinates and divide the distance by 3. Then, we add the quotient to the x-coordinate.

x-coordinate: (2 - 9) / 3 = -7/3
y-coordinate: (6 - 3 ) / 3 = 1

Adding them to the coordinates of a,
x - coordinate: (9 - 7/3) = 20/3
y - coordinate: (3 + 1) = 4
Thus, the coordinates are (20/3, 4).

7 0

3 years ago

What is the value of the underlined digit 1,711,799.

Varvara68 [4.7K]

I don't know which one is underlined so I will write it out in words.
One million seven hundred and eleven thousand and seven hundred ninety-nine.

Hope I helped :)

3 0

3 years ago

What is 1574/15 redused

r-ruslan [8.4K]

Answer:

104 14/15

Step-by-step explanation:

15 goes into 1574 104 times and you have 14 remaining so you have 104 with a remaining fraction of 14/15.

3 0

3 years ago

A survey of 80 randomly selected companies asked them to report the annual income of their presidents. Assuming that incomes are

Artyom0805 [142]

Answer:

The 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

Step-by-step explanation:

The information provided is:

$n=80\\\sigma=30,000\\\bar x=585062.50\\\text{Confidence level} = 90\%$

The critical value of <em>z</em> for 90% confidence level is, 1.645.

Compute the 90% confidence interval estimate of the mean annual income of all company presidents as follows:

$CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\\\\=585062.50\pm 1.645\times\frac{30000}{\sqrt{80}}\\\\=585062.50\pm5517.50\\\\=(579545, 590580)$

Thus, the 90% confidence interval estimate of the mean annual income of all company presidents is ($579,545, $590,580).

This interval implies that there is 90% probability that the true mean annual income of all company presidents is within this interval.

4 0

2 years ago