According to the hardy-weinberg principle, if 75% of the alleles in the gene pool are a1 and 25% are a2, what is the proportion

Question

anastassius [24]

3 years ago

12

According to the hardy-weinberg principle, if 75% of the alleles in the gene pool are a1 and 25% are a2, what is the proportion

of individuals with genotype a1a2 in this population?

Biology

1 answer:

faust18 [17] · Answer 1 · 2022-04-10T16:23:57+03:00

Frequency of allele a1 is 75%, p=0.75
Frequency of allele a2 is 25%, q=0.25
If a population is in Hardy-Weinberg equilibrium then:
p2+2pq+q2=1
<span>p2 is the frequency of genotype a1a1 (homozygous),</span>
2pq is the frequency of genotype a1a2 (heterozygous),
q2 is the frequency of genotype a2a2
<span>The proportion of individuals with genotype a1a2 is then 2*0.75*0.25=0.375 (37.5%).</span>