Answer:
Passice immunity
Explanation:
Breast milk, produced by female mammals (including humans), besides being rich in fat and protein is full of IgA. IgA is the immunoglobulin (immune system signal proteins) that is present in body secretions, such as milk.
The baby that is fed from the mother's breast ingests these defense proteins that allow it to tolerate different pathogens and toxins.
It is considered passive immunity, as it does not generate memory and depends on a continuous dose to maintain defense levels.
Answer:
cell
Explanation:
It is the smallest unit of life that can replicate independently. It's the basic structural, functional, and biological unit of all known living organisms. The study of this is called cell biology.
The thick band of fibers that connects the two hemispheres of the brain is called the corpus callosum.
<h3>
What is the function of the corpus callosum?</h3>
- The greatest connective network in the brain is the corpus callosum, which is Latin for "tough body."
- The corpus callosum is a significant mass of more than 200 million myelinated nerve fibers that connects the two hemispheres of the brain and enables the communication between the right and left sides of the brain.
- This cerebral highway serves as a conduit for the continual exchange of sensory, motor, and cognitive information.
<h3>
What is the structure of the corpus callosum?</h3>
- The roof of the lateral ventricles is made up of part of the corpus callosum.
- Four distinct neural pathways that connect various regions of the hemispheres make up the corpus callosum. The rostrum, genu, trunk or body, and splenium are the neural pathways.
- The isthmus is a thin area that lies between the trunk and the spleen.
- The tapetum, a group of fibers from the trunk and spleen, forms the roof of each lateral ventricle.
To learn more about corpus callosum visit:
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Answer:
When the patch occupancy rate (c) equals the patch extinction rate (e), patch occupancy (P) is 0
Explanation:
According to Levin's model (1969):
<em>dP/dt = c - e</em>
where P represents the proportion of occupied patches.
<em>c</em><em> </em>and <em>e </em>are the local immigration and extinction probabilities per patch.
Thus, the rate of change of P, written as dP/dt, tells you whether P will increase, decrease or stay the same:
- if dP/dt >0, then P is increasing with time
- if dP/dt <0, then P is decreasing with time
- if dP/dt = 0, then P is remaining the same with time.
The rate dP/dt is calculated by the difference between colonization or occupancy rate (<em>c</em>) and extinction rate (<em>e</em>).
c is then calculated as the number of successful colonizations of unoccupied patches as a proportion of all available patches, while e is the proportion of patches becoming empty. Notice that P can range between 0 and 1.
As a result, if the patch occupancy rate (c) equals the patch extinction rate (e), then patch occupancy P equals to 0.
