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KIM [24]
3 years ago
9

What is the equation of the line perpendicular to 2x - 3y = 13 that passes through the point (-6, 5)?

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
3 0

Answer: 2y + 3x = -8.

Step-by-step explanation:

Given our first equation 2x-3y =13, we rewrite in the form of equation of a line, i.e y = mx + c

Where m is the slope of the line and c is the intersection on y axis.

By rewriting, we have...

3y= 2x-13

y= 2x/3 - 13/3.

m= 2/3, c= -13/3.

For two perpendicular lines, the product of their gradients is -1

i.e

m¹ * m² = -1

Hence m² = -1 * 3/2

m² = -3/2.

Hence, to get the equation of the line passing through the point (-6,5) we first find the intersection when x=0 given as

[Y-c]/[x-0] = -3/2

2y - 2c = -3x

2(5) - 2c =- 3(-6)

10-18= 2c

C = -8/2

C= -4

Then the equation is given as

y = mx + c

y = [-3/2]x - 4

2y= -3x - 8

2y + 3x = -8.

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3 years ago
Melina graphed a line which passes through the points (-4, 2) and (6, 8). What is the slope of the line?
Ulleksa [173]

Answer:

The answer is

<h2>\frac{3}{5}  \\</h2>

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

m =  \frac{ y_2 - y _ 1}{x_ 2 - x_ 1}  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-4, 2) and (6, 8)

The slope is

m =  \frac{8 - 2}{6 + 4}  =  \frac{6}{10}  =  \frac{3}{5}  \\

We have the final answer as

\frac{3}{5}  \\

Hope this helps you

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3 years ago
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