Answer:
h(x) = -16x² + 192x + 208
784ft
6 sec
13 sec
Step-by-step explanation:
a)
h(x) = -16x² +vx + h
here v represent velocity
represent initial height of launch
h(x) = -16x² + 192x + 208
b)
h(x) = -16x² + 192x + 208
here a = -16
b = 192
c = 208
x = -b/2a
= -192/2(-16)
= 6
plug this value in the equation
h(x) = -16(6)² + 192(6) + 208
= 784ft
e)
Plug h(x)=0 in the equation
0 = -16x² + 192x + 208
divide equation by -16
x² - 12x - 13 = 0
Factors
1x * -13x = -13
1x - 13x = -12
Factorised form
x² - 12x - 13 = 0
x² + x - 13x - 13 = 0
x(x+1) -13(x+1) = 0
(x+1)(x-13) = 0
x = -1
x = 13
Since time can not be negative so we will reject x = -1
Answer: The required probability of event B is P(B) = 0.37.
Step-by-step explanation: For two events A and B, we are given the following probabilities :
P(A) = 0.34, P(A ∩ B) = 0.27 and P(A ∪ B) = 0.44.
We are to find the probability of event B, P(B) = ?
From the laws of probability, we have

Thus, the required probability of event B is P(B) = 0.37.
Step 2! The reason for that is the student didnt multiplied (15-2z) with -2. But she should have!
Answer:
0.50 (still the same)
Step-by-step explanation: