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Sav [38]
3 years ago
7

Which set of coordinates describes the same location as the rectangular coordinates (0,-2)

Mathematics
1 answer:
balu736 [363]3 years ago
8 0

Answer:

(0,-8)(2,-8)(2,-2)

Step-by-step explanation:

We can change each of the number at the start but than we must satisfy the other to make it a suitable shape. You can refer to any coordinates as long as it joins to form a rectangle.

If this did not satisfy you reply back.

Hope this helps and enlightens your day. Enjoy.

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user100 [1]
The value would be 63000. 
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3 years ago
I'm bad word problems can you help me​
IRINA_888 [86]

Use 12 into the equation 2+0.35m

2 + 0.35(12)

Follow PEMDAS

P= Parentheses

E= Exponents

M= Multiplication

A= Addition

S= Subtraction

2+0.35(12)

= 2 +4.2

= 6.20

Answer: $6.20

3 0
3 years ago
Help !<br><br> 174 &gt; 26.6 + 8.5n
Mekhanik [1.2K]

566353621818281727.1232321.2.23121232132312>3454535435454/.435

3 0
2 years ago
Zara translates figure p to make figure q. If she translates figure q 4 units to right to make figure r where will figure r be l
Morgarella [4.7K]

Using translation concepts, considering the vertices (x,y) of figure p, the following rule is applied to find the vertices of figure r.

(x,y) -> (x + 4, y).

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

When a figure is shifted 4 units to the right, <u>4 is added to the x-coordinate</u>, hence, considering the vertices (x,y) of figure p, the following rule is applied to find the vertices of figure r.

(x,y) -> (x + 4, y).

More can be learned about translation concepts at brainly.com/question/28416763

#SPJ1

7 0
1 year ago
Strontium-90 has a half-life of 28.8 years. If you start with a 300-gram sample of strontium-90,
Kazeer [188]

Answer:  2.66 × 10⁻¹³

<u>Step-by-step explanation:</u>

First, use the decay formula   A=A_oe^{kt}   where

  • A is the final amount (amount left)
  • A₀ is the initial amount (amount you started with)
  • k is the rate of decay (you need to solve for this)
  • t is the time

Given:

  • A = 1/2(300) = 150
  • A₀ = 300
  • k = unknown
  • t = 28.8

150=300e^{28.8k}\\\\0.5=e^{28.8k}\\\\ln(0.5)=ln(e^{28.8k})\\\\ln(0.5)=28.8k\\\\\\\dfrac{ln(0.5)}{28.8}=k\\\\\\\large\boxed{-0.0240676=k}\\

Next, input the k-value and the new t-value to solve for A.

  • A = unknown
  • A₀ = 300
  • k = -0.0240676
  • t = 1440

A=300e^{1440(-.0240676)}\\\\\large\boxed{A=2.66\times 10^{-13}}\\

5 0
3 years ago
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