y - y₁ = m(x - x₁)
y - (-1) = 4[x - (-3)]
y + 1 = 4(x + 3)
y + 1 = 4(x) + 4(3)
y + 1 = 4x + 12
- 1 - 1
y = 4x + 11
The answer is B.
Step-by-step explanation:
1)The given equations are:
x − 2y = 6 ...(i)
3x − 6y = 0 ...(ii)
Putting x = 0 in equation (i) we get
=> 0 - 2y = 6
=> y = -3
x = 0, y = -3
Putting y = 0 in equation (i) we get
⇒x-2×0=6
⇒x=6
x = 6, y = 0
Use the following table to draw the graph
x 0 6
y -3 0
Plotting the two points A(0, -3) and B(6,0) equaion (1) can be drawn
Graph of the equation ..(ii)
3x - 6y = 0 ...(ii)
Putting x = 0 in equation (ii) we get
⇒3×0-6y=0
=> y = 0
x = 0, y = 0
Putting x = 2 in equation (2) we get
⇒3×2-6y=0
=> y = 1
x = 2, y = 1
Use the following table to draw the graph.
x 0 2
y 0 1
Draw the graph by plotting the two points O(0,0) and D(2,1) from table
We see that the two lines are parallel, so they won’t intersect
Hence there is no solution
2)
Answer:
2x+6 since the +3 and -3x cancel each other out your only left with 2x
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