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Gala2k [10]
4 years ago
7

The polynomial equation x^3+x^2=-9x-9 has complex roots +/-3i What is the other root? Use a graphing calculator and a system of

equations.
Mathematics
1 answer:
Ierofanga [76]4 years ago
7 0
  For this case what you can do is factorize the <span>polynomial equation</span>, which would be left like follows
 x ^ 3 + x ^ 2 + 9x + 9 = 0
 (x + 1) (x ^ 2 + 9) = 0
 Resolving, we have that the missing root is
 x = -1
 Answer
 x=-1
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Answer:      " r  =  a  +  b  -  s "  .

_____________________________________________________

Step-by-step explanation:

_____________________________________________________

Given:  

a + b = s + r ;  Solve for:  "r" ;  that is; rewrite the equation in terms of:  " r " .

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Subtract "s" from each side of the equation;  

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    →      a + b - s  =  s + r - s  ;

    →   to get:

   →       a + b - s  =  r  ;

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 ↔   " r = a + b - s "  .

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   →  which is the answer.

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Hope this helps!

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