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ICE Princess25 [194]
3 years ago
14

A ball is launched into the sky at 272 feet per second from the roof of a skyscraper 1,344 feet tall. The equation for the ball’

s height h at time t seconds is h = -16t2 + 272t + 1344. When will the ball strike the ground?
Mathematics
1 answer:
sladkih [1.3K]3 years ago
3 0
The ball will strike the ground when h=0.
-16t²+272t+1344=0
t₁,₂=(-272+-√(272²+4*16*1344))/2*(-16)
t₁,₂=(-272+-400)/(-32)
t₁=(-272+400)/(-32)=-4 or t₂=(-272-400)/(-32)=21
Time cannot be negative value so t₂ is solution. The ball will strike the ground in 21seconds.
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inn [45]
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3 0
3 years ago
Can someone give me the answers for this ?
cupoosta [38]

Answer:

vertical angles

Step-by-step explanation:

angles 6 and 7 are formed by the same two lines and are on opposite sides  of the intersection point

6 0
3 years ago
Read 2 more answers
A diameter of a circle has endpoints p(-10,-2) and Q(4,6)
kvasek [131]

Answer:

  a) center: (-3, 2)

  b) radius: √65

  c) equation: (x +3)² +(y -2)² = 65

Step-by-step explanation:

a) The center (point A) is the midpoint of the diameter, so its coordinates are the average of the endpoint coordinates:

  A = (P +Q)/2 = ((-10, -2) +(4, 6))/2

  = (-10+4, -2+6)/2 = (-6, 4)/2

  A = (-3, 2)

__

b) The radius is the distance from the center to one end of the diameter. The distance formula can be used to find that.

  r = √((x2 -x1)² +(y2 -y1)²) = √((4-(-3))² +(6 -2)²) = √(49+16)

  r = √65

__

c) The circle centered at (h, k) with radius r has formula ...

  (x -h)² +(y -k)² = r²

So the formula for this circle is ...

  (x +3)² +(y -2)² = 65

6 0
3 years ago
Uhhhhhhhhhhhhhhhhhh what is 2+2-1=?????????
gregori [183]
2+2-1=3
2+2=4
And 4 minus 1 equals 3
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=2x%20%2B%20%5Cfrac%7B5%7D%7B8%7D%20%3D%203x%20-%20%5Cfrac%7B5%7D%7B8%7D" id="TexFormula1" titl
Whitepunk [10]

Answer:

x=\frac{5}{4}

Step-by-step explanation:

2x+\frac{5}{8}=3x-\frac{5}{8}

Subtract 5/8 from both sides:-

2x+\frac{5}{8}-\frac{5}{8}=3x-\frac{5}{8}-\frac{5}{8}

2x+\frac{5}{8}-\frac{5}{8}

Add like terms:-

  • \frac{5}{8}-\frac{5}{8}=0
  • =2x

3x-\frac{5}{8}-\frac{5}{8}

Rule:- \frac{a}{c} \pm \frac{b}{c}=\frac{a \pm b}{c}

  • \frac{-5-5}{8}

Subtract, -5-5=-10

  • =\frac{-10}{8}

Cancel common factor: 2

  • =-\frac{5}{4}
  • =3x-\frac{5}{4}

---------------

2x=3x-\frac{5}{4}

Now, subtract 3x from both sides:-

2x-3x=3x-\frac{5}{4}-3x

-x=-\frac{5}{4}

Divide both sides by -1:-

\frac{-x}{-1}=\frac{-\frac{5}{4}}{-1}

x=\frac{5}{4}

<u>OAmalOHopeO</u>

4 0
2 years ago
Read 2 more answers
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