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ICE Princess25 [194]
3 years ago
14

A ball is launched into the sky at 272 feet per second from the roof of a skyscraper 1,344 feet tall. The equation for the ball’

s height h at time t seconds is h = -16t2 + 272t + 1344. When will the ball strike the ground?
Mathematics
1 answer:
sladkih [1.3K]3 years ago
3 0
The ball will strike the ground when h=0.
-16t²+272t+1344=0
t₁,₂=(-272+-√(272²+4*16*1344))/2*(-16)
t₁,₂=(-272+-400)/(-32)
t₁=(-272+400)/(-32)=-4 or t₂=(-272-400)/(-32)=21
Time cannot be negative value so t₂ is solution. The ball will strike the ground in 21seconds.
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