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IrinaVladis [17]
3 years ago
5

Your model train has one engine and eight train cars. Find the total number of ways you can arrange the train. (The engine must

be first.)There are total ways to arrange the train.
Mathematics
1 answer:
STALIN [3.7K]3 years ago
4 0
64 arrangements I total
You might be interested in
Convert 32 kilometers per hour to miles per day. (3.28 feet 1 meter)
bonufazy [111]

Answer:

477.09 mi/da

Step-by-step explanation:

If student must use conversion given, 3.28ft = 1m, then the following works:

32km/hr = ______mi/da       1 day = 24 hrs, 1m=3.28ft, 1km=1000m,1mi=5280ft

32km/hr  x  24hr/day  x  1000m/1km  x  3.28ft/1m  x  1mi/5280ft  = 477.09mi/da

If student can use 1km = 0.62mi, some steps can be skipped.

3 0
3 years ago
You purchase a car worth $25077 and make a down payment of $3560. You intend to repay the balance of the car with month end car
zubka84 [21]

Answer:

value of buyout is $4185.74

Step-by-step explanation:

given data

car worth = $25077

down payment = $3560

monthly payment = $336 = 336 × 6 = $2016 per semi annually

time = 5 year  = 10 half yearly

rate = 4.04 %

to find out

value of final buyout

solution

we know here loan amount will be 25077 - 3560 = $21517

and we find present value first by formula that is

present value = \frac{amount(1+r)^t - 1}{r (1+r)^t}

put here t = 10 and r = \frac{4.04}{200}

so

present value = \frac{2016(1+\frac{4.04}{200})^10 - 1}{r (1+\frac{4.04}{200})^10}

present value = 18089.96

so

loan unpaid amount is here

loan unpaid amount = 21517 - 18089.96

loan unpaid amount = $3427.04

so

now we calculate value of buyout

that is express as

amount = principal × (1+r)^{t}

amount = 3427.04 × (1+\frac{4.04}{200})^{10}

amount = 4185.74

so value of buyout is $4185.74

7 0
3 years ago
1. How many groups of days are in 1 week?
wolverine [178]

Answer:

(14 groups)

14 divided by 7 = 2

Therefore 14 is your answer

Step-by-step explanation:

lol that's all I got

3 0
2 years ago
92 divided by 4 use partial and quotients to divide
kherson [118]
The partial quotient is 23
8 0
3 years ago
Read 2 more answers
In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

5 0
3 years ago
Read 2 more answers
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