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Alisiya [41]
3 years ago
7

The force of gravity pulls down on your school with a total force of 400,000 newtons. The force of gravity pulling down on your

school would be exactly twice as much if your school:
Physics
1 answer:
Marina CMI [18]3 years ago
4 0

Explanation:

It is given that, the force of gravity pulls down on your school with a total force of 400,000 N.

The force of gravity is given by the formula as follows :

F = mg

m is mass and g is the acceleration due to gravity

Mass of an object remains same always. But if the mass of your school becomes twice of the initial mass, the force of gravity pulling down on your school would be exactly twice.

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0.3-L glass of water at 20C is to be cooled with ice to 5C. Determine how much ice needs to be added to the water, in grams, i
abruzzese [7]

Answer:

a. m_i_c_e=54.6g\\b. m_i_c_e=48.7g\\m_c_o_l_d_w_a_t_e_r=900g

Explanation:

First we need to state our assumptions:

Thermal properties of ice and water are constant, heat transfer to the glass is negligible, Heat of ice h_i_f=333.7KJkg

Mass of water,m_w=\rho V =1\times0.3=0.3Kg.

Energy balance for the ice-water system is defined as

E_i_n-E_o_u_t=\bigtriangleup E_s_y_s\\0=\bigtriangleup U=\bigtriangleup U_i_c_e+\bigtriangleup U_w

a.The mass of ice at 0\textdegree C is defined as:

[mc(0-T_1)+mh_i_f+mc(T_2-0)]_i_c_e+[mc(T_2-T_1)]_w=0\\\\m_i_c_e[0+333.7+418\times(5-0)]+0.3\times4.18\times(5-20)=0\\m_i_c_e=0.0546Kg=54.6g

b.Mass of ice at 20\textdegree C is defined as:

[mc(0-T_1)+mh_i_f+mc(T_2-0)]_i_c_e+[mc(T_2-T_1)]_w=0\\\\m_i_c_e[2.11\times(0-(20))+333.7+4.18\times(5-0)]+0.3\times4.18\times(5-20)=0\\\\m_i_c_e=0.0487Kg=48.7g

c.Mass of cooled water at T_c_w=0\textdegree C

\bigtriangleup U_c_w+\bigtriangleup U_w=0

[mc(T_2-T_1)]_c_w+[mc(T_2-T_1)]_w=0\\m_c_w\times4.18\times(5-0)+0.3\times4.18\times(5-20)\\m_c_w=0.9kg=900g

8 0
3 years ago
A baseball team is practicing throwing balls vertically upward to test their throwing arms. A player manages to throw a ball tha
Nitella [24]
We can solve this problem using the law of conservation of energy.
This law states that energy in a closed system must stay same.
That means that the energy of a ball leaving the hand and the energy of a ball when it reaches its maximum height must be the same.
The energy of a ball leaving the players hand is kinetic energy:
E_k=\frac{mv^2}{2}
The energy when the ball reaches its maximum height ( and has zero velocity) is potential energy in a gravitational field:
E_p=mgh
As said before these energies must be the same, and that allows us to find the initial speed:
E_k=E_p\\
\frac{mv^2}{2}=mgh\\
v^2=2gh\\
v=\sqrt{2gh}
When we plug in all the number we get that v=14\frac{m}{s}

7 0
3 years ago
What makes the subject of star formation so difficult and complex?
sdas [7]
Stars live to long for just one person to see it die, usually it out lives all of us
5 0
3 years ago
10. A man throws a water balloon down off the edge of a building. If he wants the water
stepladder [879]

Answer:

intinal speed should be 10

Explanation:

v = v0 + at

30 = v0 +10.2

then v0= 10

5 0
3 years ago
What is the radius of a force?
vazorg [7]

Answer:

this kind of force is proportional directly to the speed of the object and inversely to the radius of the curved path. Therefore, Hence, the force becomes 2.25 times the original force.

Explanation:

6 0
2 years ago
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