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Alisiya [41]
3 years ago
7

The force of gravity pulls down on your school with a total force of 400,000 newtons. The force of gravity pulling down on your

school would be exactly twice as much if your school:
Physics
1 answer:
Marina CMI [18]3 years ago
4 0

Explanation:

It is given that, the force of gravity pulls down on your school with a total force of 400,000 N.

The force of gravity is given by the formula as follows :

F = mg

m is mass and g is the acceleration due to gravity

Mass of an object remains same always. But if the mass of your school becomes twice of the initial mass, the force of gravity pulling down on your school would be exactly twice.

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A simple harmonic wave of wavelength 18.7 cm and amplitude 2.34 cm is propagating along a string in the negative x-direction at
storchak [24]

Answer

given,

wavelength = λ = 18.7 cm

                    = 0.187 m

amplitude , A = 2.34 cm

v = 0.38 m/s

A)  angular frequency = ?

     f = \dfrac{v}{\lambda}

     f = \dfrac{0.38}{0.187}

     f =2.03\ Hz

angular frequency ,

ω = 2π f

ω = 2π x 2.03

ω = 12.75 rad/s

B) the wave number ,

      K = \dfrac{2\pi}{\lambda}

     K= \dfrac{2\pi}{0.187}

    K =33.59\ m^{-1}

C)

as the wave is propagating in -x direction, the sign is positive between x and t

y ( x ,t) = A sin(k  x - ω t)

y ( x ,t) = 2.34  x  sin(33.59 x - 12.75 t)

4 0
3 years ago
A student throws a rock horizontally off a 5.0 m tall building. The rock's initial speed is 6.0 m/s. How long will it take the r
Archy [21]

Answer:

The time taken by the rock to reach the ground is 0.569 seconds.

Explanation:

Given that,

A student throws a rock horizontally off a 5.0 m tall building, s = 5 m

The initial speed of the rock, u = 6 m/s

We need to find the time taken by the rock to reach the ground. Using second equation of motion to find it. We get :

s=ut+\dfrac{1}{2}gt^2\\\\5=6t+\dfrac{1}{2}\times 9.8t^2\\\\t=0.569\ seconds

So, the time taken by the rock to reach the ground is 0.569 seconds. Hence, this is the required solution.

5 0
3 years ago
Read 2 more answers
When light reflects on a mirror, does it undergo a phase change?
Lynna [10]
The light does not undergo a phase change.

Also, the surface of a mirror is a rigid boundary.
5 0
3 years ago
In Pensacola in June, high tide was at noon. The water level at high tide was 12 feet and 2 feet at low tide. Assuming the next
Sveta_85 [38]
<span>To answer this question, the equation that we will be using is:
 y = A cos bx + c
 where A = amplitude, b = 2 pi/Period, Period = 12 hrs, c = midline,
  x = t and y = f(t)

  A = 1/2 (Xmax - Xmin)
12 - 2 / 2 = 10/2 = 5
  b = 2 pi / 12 = pi/6
  c = 1/2 (Xmax + Xmin)
  12+2/2 = 7
  answer: f(t) = 5 cos pi/6 t + 7 </span>
8 0
4 years ago
A 500-kg roller coaster car travels with some initial velocity along a track that is 5 m above the ground. The car goes down a s
LUCKY_DIMON [66]

Answer:

12m/s

Explanation:

4 0
3 years ago
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