Sneaky question.
The secondary voltage will be zero.
Secondary voltage is the result of CHANGES in the primary voltage. That means the primary is energized with AC. The transformer in this question is energized with DC, which doesn't change. So there is no secondary voltage, this transformer doesn't work, and what you get out of it is: Smoke !
I am going to say velocity because you have the same amount of acceleration going in a certain direction.
Given: Initial velocity of toy car (u ) = 0
Final velocity of toy car (v) = 0.12 m/s
Required time (t) = 0.1 s
To find: The acceleration of the toy car.
Let the acceleration of the toy car be (a)
Formula Used: 1st kinematic equation of motion
v = u + at ---------------------------(i)
Here, all alphabets are in their usual meanings
Now, from equation (i), we shall calculate the value of 'a'.
so, a = (v - u) /t
or, a = (0.12 m/s - 0) / 0.1s
or, a = 1.2 m/s²
Hence, the required acceleration of the toy car will be 1.2 m/s².
The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.
<h3>What is image distance?</h3>
This is the distance between the image formed and the focus when an object is placed in front of a plane mirror.
To calculate the image distance, we use the formula below.
Formula:
- 1/f = 1/u+1/v........... Equation 1
Where:
- f = Focal length of the mirror
- v = Image distance
- u = object distance
From the question,
Given:
Substitute these values into equation 1 and solve for the image distance
- 1/0.45 = 1/0.25 + 1/v
- 2.22 = 4+1/v
- 1/v = 2.22-4
- 1/v = -1.78
- v = 1/(-1.78)
- v = -0.56 m
Hence, The image distance is -0.56 m.
Learn more about image distance here: brainly.com/question/17273444
Answer:
The function has a maximum in 
The maximum is:

Explanation:
Find the first derivative of the function for the inflection point, then equal to zero and solve for x




Now find the second derivative of the function and evaluate at x = 3.
If
the function has a maximum
If
the function has a minimum

Note that:

the function has a maximum in 
The maximum is:
