Question

A 30.6 kg mass attached to a spring oscillates with a period of 3.45 s. Find the force constant of the spring.

Answer 1

Answer:

Force constant, K = 101.49 N/m

Explanation:

It is given that,

Mass, m = 30.6 kg

Time period of oscillation, T = 3.45 s

We need to find the force constant of the spring. The time period of the spring is given by :

$T=2\pi\sqrt{\dfrac{m}{K}}$

$K=\dfrac{4\pi^2m}{T^2}$

$K=\dfrac{4\pi^2\times 30.6\ kg}{(3.45\ s)^2}$

K = 101.49 N/m

So, the force constant of the spring is 101.49 N/m. Hence, this is the required solution.