What is the radius of a force?

Physics

1 answer:

vazorg [7]1 year ago

6 0

Answer:

this kind of force is proportional directly to the speed of the object and inversely to the radius of the curved path. Therefore, Hence, the force becomes 2.25 times the original force.

Explanation:

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Help with question 16 and 17

storchak [24]

Your answer is correct.

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The fractional change in resistance is equal to the given temperature coefficient multiplied by the change in temperature.

R = R₀×(1 + α×ΔT)

R = (10.0 Ω)×(1 + 0.004×(65 -20)) = 11.8 Ω

5 0

3 years ago

where σ(t) and σ(0) represents the time-dependent and initial (i.e., time =0) stresses, respectively, and t and τ denote elapsed

lesya [120]

Answer:

$E_r(6)=4.35614\ MPa$

Explanation:

$\epsilon$ = Strain = 0.49

$\sigma _0$ = 3.1 MPa

At t = Time = 32 s $\sigma$ = 0.41 MPa

$\tau$ = Time-independent constant

Stress relation with time

$\sigma=\sigma _0exp\left(-\frac{t}{\tau}\right)$

at t = 32 s

$0.41=3.1exp\left(-\frac{32}{\tau}\right)\\\Rightarrow exp\left(-\frac{32}{\tau}\right)=\frac{0.41}{3}\\\Rightarrow -\frac{32}{\tau}=ln\frac{0.41}{3}\\\Rightarrow \tau=-\frac{32}{ln\frac{0.41}{3}}\\\Rightarrow \tau=16.0787\ s$